Symfony2 Twig 获取子实体的总数 [英] Symfony2 Twig Get Total Count for Child Entity

问题描述

存在以下实体:农场、谷仓和动物.一个农场可以有很多谷仓，一个谷仓可以有很多动物.

The following entities exist, Farm, Barn and Animals. A Farm can have many Barns and a Barn many Animals.

在 TWIG 模板中显示农场时，还应显示动物数量.

When displaying a Farm in a TWIG template the number of Animals should be shown as well.

最好的方法是什么?

我创建了一个 TWIG 扩展，它可以让我轻松显示谷仓的数量.

I have create a TWIG extension which allows me to easily show the number of barns.

public function totalFieldFilter($data, $getField='getTotal') {
    $total = count($data->$getField());
    return $total;
}

在我的模板中，我将使用 {{ farm|totalField('getBarns') }}，我可以轻松地扩展它来编写另一个自定义函数，如下所示:

In my template I would use {{ farm|totalField('getBarns') }}, I could easily extend this to write another custom function like so:

public function totalFieldFilter($farm) {
    $total = 0;
    foreach($farm->getBarns() AS $barn) {
        $total += count($barn->getAniamls());
    }
    return $total;
}

虽然这行得通，但有没有更好的方法，可以使其更通用吗?如果我想计算动物的腿怎么办?或者一个谷仓有多少扇门，我每次都必须编写一个自定义的 TWIG 扩展.

Although this would work, is there a better way and can it be made more generic? What if I wanted to count Legs on Animals? Or how many Doors a Barn has, I would have to write a custom TWIG extension each time.

推荐答案

使用实体访问器 :

{% for farm in farms %}

  {{ farm.name }}

  {% set barns = farm.getBarns() %}

  Barns count = {{ barns|length }}

  {% for barn in barns %}

    {% set animals = barn.getAnimals() %}

    {{ barn.name }} animals count : {{ animals|length }}

  {% endfor %}

{% endfor %}

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