数组作为函数的参数 [英] array as function argument

问题描述

考虑以下code：

#define MAX_COUNT 4
static int foo(int w[MAX_COUNT])
{
    int *p = w;

    if (w) {
        w[0] = 10; w[1] = 20; w[2] = 30; w[3] = 40;
    }

    return 0;
}

它便携式和法律传递NULL是定义foo的上述（）（例如，对于一个情况时我不需要W []改变）？假设一个数组的名字是一个指向它的第一要素，在我看来，它应该是好的，但perhpas我失去了一些东西？

is it portable and legal pass NULL to above defined foo() (for example, for a situation when I don't need w[] be altered)? Given that the name of an array is a pointer to its first element, it seems to me that it should be OK, but perhpas I'm missing something?

谢谢！

推荐答案

这应该罚款。你传递的数组中元素的数量仅仅是形式主义，并没有真正需要的。 是W 只是一个指针 INT 。有没有其他运行时或编译检查。

It should be fine. The number of elements in the array that you passed are merely a formalism, and not really needed. w is just a pointer to int. There is no other runtime or compilation check.

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