PHP爆阵帮助 [英] php imploding array help

问题描述

我想给破灭了用户ID的$ users_in_range阵列的问题是，它是iploding英里，而不是用户ID在

 ＆LT; PHP
$ users_in_range = users_in_range（$经纬度，$长，500，真正的）;//爆用户到mysql友好名单
$ comma_separated =破灭（，，$ users_in_range）;
回声$ comma_separated;//这只是输出，同时调试
的foreach（$ users_in_range为$用户id =＆GT; $ miles_away）{
    回声用户名=＆LT; B＆GT; $用户用户名与LT; / B＆GT;为＆lt; B＆GT; $ miles_away＆LT; / B＆GT;从我英里远＆LT; BR /＆gt;中;
}
？＆GT;
 

解决方案

该用户ID为阵列的关键，所以你需要做的：

  $ comma_separated =破灭（，array_keys（$ users_in_range））;
 

I am trying to the implode the userIDs in the $users_in_range array the problem is it is iploding miles instead of userid

<?PHP
$users_in_range = users_in_range($lat, $long, 500, true); 

// implode users into mysql friendly list
$comma_separated = implode(",", $users_in_range);
echo $comma_separated;

// this is just for output while debugging
foreach ($users_in_range as $userid => $miles_away) {
    echo "UserID=<b>$userid</b> is <b>$miles_away</b> miles away from me.<br />";
}
?>

解决方案

The userid is the key of the array, so you need to do:

$comma_separated = implode(",", array_keys($users_in_range));

这篇关于PHP爆阵帮助的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！