类型错误:需要一个类似字节的对象,而不是“str"-python 2 到 3 [英] TypeError: a bytes-like object is required, not 'str' - python 2 to 3

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问题描述

您好,我遇到了此错误消息的问题.我是 Python 新手,这个 Python2 和 Python3 很麻烦.我不知道在这里做什么,错误信息如下所示.

Hi I am having trouble with this error message. I am new to Python and this Python2 and Python3 is a hassle. I'm not sure what to do here, the error message is as shown below.

Using Ticker: AAPL
    Traceback (most recent call last):
      File "realtime.py", line 18, in <module>
        r=requests.get(auth_url, headers={"Authorization": "Basic %s" % base64.b64encode(os.environ['INTRINIO_USER'] + ":" + os.environ['INTRINIO_PASSWORD'])})
      File "C:\Users\User\AppData\Local\Programs\Python\Python36-32\lib\base64.py", line 58, in b64encode
        encoded = binascii.b2a_base64(s, newline=False)
    TypeError: a bytes-like object is required, not 'str'

我使用的代码如下所示.

The code I am using is as shown below.

import websocket
import _thread
import time
import requests
import base64
import json
import sys
import os
from requests.auth import HTTPBasicAuth

try:
    print ("Using Ticker: " + str(sys.argv[1]))
except:
    print ("Please include ticker as first argument")
    sys.exit()

auth_url = "https://realtime.intrinio.com/auth";
r=requests.get(auth_url, headers={"Authorization": "Basic %s" % base64.b64encode(os.environ['INTRINIO_USER'] + ":" + os.environ['INTRINIO_PASSWORD'])})

socket_target = "wss://realtime.intrinio.com/socket/websocket?token=%s" % (r.text)

def on_message(ws, message):
    try:
        result = json.loads(message)
        print (result["payload"])
    except:
        print (message)

def on_error(ws, error):
    print ("###ERROR### " + error)

def on_close(ws):
    print ("###CONNECTION CLOSED###")

def on_open(ws):
    def run(*args):
        security = "iex:securities:" + str(sys.argv[1]).upper()
        message = json.dumps({"topic": security,"event": "phx_join","payload": {},"ref": "1"})
        ws.send(message)
    thread.start_new_thread(run, ())


websocket.enableTrace(True)
ws = websocket.WebSocketApp(socket_target, on_message = on_message, on_error = on_error, on_close = on_close)
ws.on_open = on_open
ws.run_forever()

推荐答案

您应该将 str 编码为 bytes.

You should encode str into bytes.

data_string = os.environ['INTRINIO_USER'] + ":" + os.environ['INTRINIO_PASSWORD']

data_bytes = data_string.encode("utf-8")

base64.b64encode(data_bytes)

这篇关于类型错误:需要一个类似字节的对象,而不是“str"-python 2 到 3的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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