实例化一个 TypeVar 类型 [英] Instantiate a type that is a TypeVar
问题描述
作为一个 C++ 程序员,下面的代码对我来说似乎很自然,但它不能运行:
As a C++ programmer the following code seems very natural to me but it doesn't run:
from typing import TypeVar, Generic, List, NewType
TPopMember = TypeVar('TPopMember')
Population = NewType('Population', List[TPopMember])
class EvolutionaryAlgorithm(Generic[TPopMember]):
def __init__(self, populationSize: int) -> None:
# The following raises TypeError: 'TypeVar' object is not callable
self.__population = Population([TPopMember() for _ in range(populationSize)])
显然 Python 无法实例化实际上是 TypeVars 的类(TPopMember).我只是想创建一个列表(人口),其中有几个默认初始化(在 Python 中你怎么说?)TPopMembers.我应该怎么做?
Apparently Python isn't able to instantiate classes (the TPopMember) that are actually TypeVars. I simply want to create a list (Population) with a couple of default initialized (how do you say that in Python?) TPopMembers. How should I go about this?
我使用的是 Python 3.7.2.
I'm using Python 3.7.2.
推荐答案
您没有意识到类型提示是一种提示.换句话说,根本不要认为它是一种类型.您无法实例化它们.
You didn't realize that type hint is a hint. In other words, don't think it is a type at all. You can't instantiate them.
我从您的评论中了解到,您的意图是做 C++ 模板允许您做的事情.所以这是我实现这一目标的方法:
As I understand from your comment, your intention is doing what C++ template allows you to do. So here is my way to achieve that:
from typing import TypeVar, Generic, List, NewType, Type
import random
class PopMember:
def __init__(self):
self.x = random.randint(0, 100)
def __repr__(self):
return "Pop({})".format(self.x)
TPopMember = TypeVar("TPopMember")
Population = NewType('Population', List[TPopMember])
class EvolutionaryAlgorithm(Generic[TPopMember]):
def __init__(self, member_class: Type[TPopMember], populationSize: int) -> None:
self.__population = Population([member_class() for _ in range(populationSize)])
def __repr__(self):
return "EA({})".format(self.__population)
x = EvolutionaryAlgorithm(PopMember, 5)
print(x)
输出:
EA([Pop(49), Pop(94), Pop(24), Pop(73), Pop(66)])
你必须明白的是,如果你从 Generic[T]
派生了一个类,你需要在创建类时以某种方式使用 T
.在我的示例中,我 创建了一个虚拟对象并解析它的类并启动它.通常我不会以这种方式编写,我可以将一个类作为参数 将一个类传递给构造函数以请求生成此特定类型的项,因为类本身与其实例不同,是也是一个 Python 对象.(感谢chepner的建议)
What you have to understand is that, if you derived a class from Generic[T]
, you need to use T
some how when you create your class. In my example I create a dummy object and resolve its class and initiate it. Normally I would not write in this way, I can just throw in a class as parameber pass in a class to the constructor to request to generate items of this particular type because class itself, distinct from an instance of it, is also a Python object. (thanks chepner for the suggestion)
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