可以制作随机类型的方法吗? [英] Possible to make a method with random type?

问题描述

问候

我想知道是否可以创建一个随机类型的方法.

I'm wondering if it is possible to create a single method with a random type.

类似于:

public static T CheckWhatTIs(object source)
{
    MessageBox.Show("T = " + T.GetType());
}

当我将它用作 CheckWhatTIs(true) 时，我会在哪里得到T = bool"；并在我将其用作 CheckWhatTIs(1) 时获得T = int"；

where I would get "T = bool" when I use it as CheckWhatTIs(true); and get "T = int" when I use it as CheckWhatTIs(1);

有没有可能做到这一点?

Is it possible to accomplish this ?

推荐答案

public static void CheckWhatTIs<T>(T source)
{
    MessageBox.Show("T = " + source.GetType());
}

几点说明:

1. 该函数没有返回类型，因为您只是显示一个消息框
2. 如果您想将其用作 CheckWhatTIs(1) 和 CheckWhatTIs(true) 不要将其声明为扩展方法，请删除 this来自参数.

1. The function has no return type as you are just showing a message box
2. If you want to use it as CheckWhatTIs(1) and CheckWhatTIs(true) don't declare it as an extension method, remove this from the parameters.

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