TypeScript 从函数接口中选择调用签名 [英] TypeScript pick call signature from function interface

问题描述

有一个带有静态的函数接口:

There is a function interface with statics:

interface MyFunction {
  (value: string): string;
  a: string;
  b: string;
}

我如何仅选择调用签名(忽略a和b)?

How do I Pick the call signature only (ignore a and b)?

推荐答案

您不能选择调用签名，因为它不是您界面的属性.
你可以做下一步:

You cannot Pick a call signature as it is not a property of your interface.
You can do next:

interface MyFunction {
    (value: string): string;
    a: string;
    b: string;
}

type Callable<T> = T extends (...args: any[]) => any ? (...args: Parameters<T>) => ReturnType<T> : never;

type MyFunctionCallSignature = Callable<MyFunction>;

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