TypeScript:元组类型到对象类型 [英] TypeScript: tuple type to object type

查看:43
本文介绍了TypeScript:元组类型到对象类型的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

考虑这样的元组:

type MyTuple = [A, B];

其中AB 都有一个名为key 的属性.例如,

where A and B both have an attribute named key. For instance,

interface A = {
  key: 'sandwiches'
}

interface B = {
  key: 'pasta'
}

我想要以下界面:

interface Result {
  sandwiches: A;
  pasta: B;
}

有没有办法动态地做到这一点?

Is there a way to do this dynamically?

我在想,如果这是可以实现的,它可能看起来像:

I'm thinking that, if this is achievable, it might look something like:

type MapTuple<T> = {
  [K in keyof T]: T[K]["key"]
}

但这不起作用.

这个问题是 Typescript 的:对象类型到数组类型(元组)

This question is the inverse of Typescript: object type to array type (tuple)

推荐答案

这将产生预期的效果.您需要映射元组的所有键属性并为每个键提取元组成员:

This will produce the desired effect. You need to map over all the key properties of the tuple and extract the tuple member for each key :

type MyTuple = [A, B];

interface A {
  key: 'sandwiches'
}

interface B {
  key: 'pasta'
}


type MapTuple<T extends Array<{ key: string }>> = {
  [K in T[number]['key']]: Extract<T[number], { key : K}>
}

type R = MapTuple<MyTuple>

这篇关于TypeScript:元组类型到对象类型的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆