从另一个 Popover 中关闭显示为 Popover segue 的 ViewController [英] Dismissing a ViewController shown as Popover segue from within another Popover

问题描述

我的故事板正在使用 UINavigationController(VC0)，我继续使用 UIPopover 加载新的 UIViewController (VC1).从这个新的 UIViewController，我弹出一个新的 UIViewController (VC2).当我尝试关闭这个最新的弹出框时，我正在退出 UINavigationController.

My storyboard is using a UINavigationController(VC0), I segue using a UIPopover to load a new UIViewController (VC1). From this new UIViewController, I am popping to a new UIViewController (VC2). When I attempt to close this newest popover, I am being quit back to the UINavigationController.

我在 VC0 中用于将 VC1 显示为弹出框的代码，VC1 到 VC2 是相同的代码(尽管标识符不同):

The code that I'm using in VC0 to show the VC1 as popover, VC1 to VC2 is the same code (different identifier though):

[self performSegueWithIdentifier:@"titlePopover" sender:self];

我在 VC2 中用来关闭弹出框的代码是:

The code that I'm using in VC2 to dismiss the popover is:

UIViewController *vc = [self presentingViewController];
[self dismissViewControllerAnimated:YES completion:^{
    [[vc presentingViewController] dismissViewControllerAnimated:YES completion:nil];
}];

它所做的是关闭 VC2，显示 VC1 一瞬间，然后关闭 VC1 并返回到 VC0.我只想关闭 VC2，这样我就可以使用 VC1

What it does is dismisses VC2, shows VC1 for a split second, then dismisses VC1 and goes back to the VC0. I want to be able to dismiss VC2 only, so that I'm on VC1

推荐答案

如果以模态方式执行 sugue，请使用代码导航:

If you performing sugue modally, use code navigate back:

[self dismissViewControllerAnimated:YES completion:nil];

如果执行推segue，使用代码导航回来:

If performing push segue, use code to navigate back:

[self.navigationController popViewControllerAnimated:YES];

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