搜索 UITableView 并忽略标点符号 [英] Searching a UITableView and ignoring punctuation

问题描述

有没有办法搜索 UITableView 并忽略某些字符(如逗号或点)?

Is there a way to search through a UITableView and ignore certain characters like commas or dots?

即我想搜索St George"，但我的数据集包含St. George"，因此结果始终为零.

I.e. I would like to search for "St George" but my data set contains "St. George" so the result is always zero.

已编辑的问题:

 func filteredArray(searchText: NSString) {
    if searchText == "" {
        array_search = array_all
    } else {
        showTableViewResults()
        array_search.removeAll()
        for i in 0 ..< array_all.count {
            let object:MyObject = array_all[i]
            let languageSearchString = object.myObjectName
            let searchStr:String = languageSearchString!
            if searchStr.lowercased().contains(searchText.lowercased) {
                array_search.append(object)
            }
        }
    }
    tableView.reloadData()
    recordsFoundLabel.text = "records found: \(array_search.count)"
}

推荐答案

在执行搜索之前，您可以从字符串中过滤掉所有不是字母的字符.这同样适用于表视图数据源元素.同样如 rmaddy 所述，您应该实现不区分大小写的搜索:

You can filter all characters thats not a letter out of your String before performing your search. The same applies to the table view data source elements. Also as mentioned by rmaddy you should implement a case insensitive search:

编辑/更新 Swift 5.2 或更高版本

extension StringProtocol {
    func caseInsensitiveContains<S: StringProtocol>(_ string: S) -> Bool { range(of: string, options: .caseInsensitive) != nil }
}

---

extension StringProtocol where Self: RangeReplaceableCollection {
    var letters: Self { filter(\.isLetter) }
}

---

测试:

---

Testing:

let search = "st george"
let tableViewSource = ["Apple", "Orange", "Banana", "St. George"]

let filtered = tableViewSource.filter {
    $0.letters.caseInsensitiveContains(search.letters)
}
print(filtered)   // ["St. George"]

---

---

如果您只想从字面上删除字符串中的标点符号(请注意，这会保留字符串中的空格)，您可以执行以下操作:

---

---

If you would like to literally just remove punctuation from your String (note that would keep the spaces in your String), you can do as follow:

extension StringProtocol where Self: RangeReplaceableCollection {
    mutating func removePunctuation() { removeAll(where: \.isPunctuation) }
}

---

extension Bool {
    var negated: Bool { !self }
}

---

extension StringProtocol where Self: RangeReplaceableCollection {
    var removingPunctuation: Self { filter(\.isPunctuation.negated) }
}

---

测试:

---

Testing:

let filtered = tableViewSource.filter {
    $0.removingPunctuation.caseInsensitiveContains(search.removingPunctuation)
}
print(filtered)   // ["St. George"]

---

如果您想实现与 Xcode 自动完成相同的逻辑，您需要搜索每个字符并更改搜索字符串的 startIndex:

---

If you would like to implement the same logic as Xcode autocomplete you would need to do a search for each character and change the startIndex of the string searched:

extension StringProtocol where Self: RangeReplaceableCollection {
    func containsCharactersInSequence<S: StringProtocol>(_ string: S, options: String.CompareOptions = []) -> (result: Bool, ranges: [Range<Index>]) {
        var found = 0
        var startIndex = self.startIndex
        var index = string.startIndex
        var ranges: [Range<Index>] = []
        while index < string.endIndex,
            let range = self[startIndex...].range(of: string[index...index], options: options) {
            ranges.append(range)
            startIndex = range.upperBound
            string.formIndex(after: &index)
            found += 1
        }
        return (found == string.count, ranges)
    }
}

---

游乐场测试:

---

Playground Testing:

let search = "stgre"
let tableViewSource = ["Apple", "Orange", "Banana", "St. George"]

let filtered = tableViewSource.filter {
    $0.containsCharactersInSequence(search, options: .caseInsensitive).result
}
print(filtered)   // ["St. George"]

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