击阵列与阵列元件的每一个字符作为一个字符串的字符 [英] Bash array with each character of that array element as a character of a string

问题描述

我试图循环虽然在bash的数组。该数组是AARON目前该数组填充索引0亚伦。我想被表现为如

I am trying to loop though an array in bash. The array is "AARON" currently that array fills index 0 with AARON. I want to be behave as such

ARA [0] = A

ARA [1] = A

ARA [2] = R

ARA [3] = O

ARA [4] = N

ara[0] = A
ara[1] = A
ara[2] = R
ara[3] = O
ara[4] = N

我的剧本目前看起来是这样的。

My script currently looks like this.

#!/bin/bash
declare count
declare -a ara=(AARON)

for name in {A..Z}
do
        count=$((count++))
        for char in ${ara[*]}
        do
                if [[ ${ara[char]} -eq $name ]]
                echo ${ara[char]} # for debugging purposes.
                then
                        sum=$((sum + count))
                fi
        done
done

echo $sum #for debugging purposes.

通常我会通过设置自定义IFS实现这一点，但我不知道我会怎么做，对于字符串的每个字符。

Normally I would achieve this by setting a custom IFS but I don't know how I would do that for each character of string.

推荐答案

您想 = 不是 -eq 的字符串比较。

You want = not -eq for string comparison.

您回声$ {ARA [字符]} 行是你的如果测试不是一部分一部分的如果的身体。

Your echo ${ara[char]} line is part of your if test not part of the if body.

您计数= $（（计数++））分配无法正常工作（它总是设置计数来零）你想（（计数++））或计数= $（（++数））代替。

Your count=$((count++)) assignment doesn't work correctly (it always sets count to zero) you want ((count++)) or count=$((++count)) instead.

您可以使用 $ {strvar：POS：计数} 来得到一个字符串的一部分

You can use ${strvar:pos:count} to get parts of a string.

因此​​，像这样：

#!/bin/bash
declare count
declare -a ara=(AARON)

for name in {A..Z}
do
        ((count++))
        for ((i=0; i<=${#ara[0]}; i++))
        do
                echo ${ara[0]:i:1} # for debugging purposes.
                if [[ ${ara[0]:i:1} = $name ]]
                then
                        sum=$((sum + count))
                fi
        done
done

echo $sum # for debugging purposes.

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