无法添加数组值，有什么不对？ [英] Cannot add array values, what's wrong?
问题描述
我正在委托有一个电子商务Web应用程序的功能之一，我的工作就可以了。
I am making an eCommerce web application having commission as one of the feature and I am working on it.
Orders表：
CREATE TABLE `orders` (
`OrderId` int(11) NOT NULL AUTO_INCREMENT,
`OrderCode` varchar(20) NOT NULL,
`CustEmailAdd` varchar(80) NOT NULL,
`CustDelAddId` varchar(255) NOT NULL,
`ProdCode` varchar(255) NOT NULL,
`Quantity` varchar(100) NOT NULL,
`PaytMethod` varchar(255) NOT NULL,
`ShippingCharges` float NOT NULL,
`TaxedAmount` float NOT NULL,
`AppliedCredits` int(11) NOT NULL,
`PayableAmount` varchar(255) NOT NULL,
`OrderDate` datetime NOT NULL,
`OrderModified` datetime NOT NULL,
`OrderStatus` varchar(255) NOT NULL,
`OrderIPAddress` varchar(20) NOT NULL,
PRIMARY KEY (`OrderId`)
) ENGINE=InnoDB AUTO_INCREMENT=3 DEFAULT CHARSET=utf8
佣金表：
CREATE TABLE `commission` (
`CommId` int(11) NOT NULL AUTO_INCREMENT,
`OrderCode` varchar(20) NOT NULL,
`ProdCode` varchar(255) NOT NULL,
`ModCode` varchar(255) NOT NULL,
`AffiCode` varchar(255) NOT NULL,
`BenCode` varchar(255) NOT NULL,
`ModCommAmount` varchar(255) NOT NULL,
`AffiCommAmount` varchar(255) NOT NULL,
`BenCommAmount` varchar(255) NOT NULL,
PRIMARY KEY (`CommId`)
) ENGINE=InnoDB AUTO_INCREMENT=3 DEFAULT CHARSET=utf8
该affiliate_commission_payable表
The affiliate_commission_payable table
CREATE TABLE `affiliate_commission_payable` (
`ACP_Id` int(11) NOT NULL AUTO_INCREMENT,
`CommId` int(11) NOT NULL,
`ACP_PaymentStatus` varchar(255) NOT NULL,
`ACP_PaymentDate` varchar(255) NOT NULL,
`ACP_PaymentDetails` text NOT NULL,
PRIMARY KEY (`ACP_Id`)
) ENGINE=InnoDB AUTO_INCREMENT=3 DEFAULT CHARSET=utf8
我有一个数组，像这样：
I have an array like so:
// For Order 000001
Array
(
[0] => ORD-000001
)
Array
(
[Paid] => 26.25
[Due] => 42.75
)
// For Order 000002
Array
(
[0] => ORD-000002
)
Array
(
[Cancelled] => 33.75
[Due] => 13.5
)
// For Order 000003
Array
(
[0] => ORD-000003
)
Array
(
[Paid] => 13.50
[Paid] => 14.25
)
我所试图做的是显示的顺序佣金汇总给用户。它是在像这样的表格式为：
What I am trying to do is showing the order commission summary to the user. It is in the table format like so:
OrderCode Paid Comm Cancelled Comm Due Comm View Details
ORD-000001 addAllPaid addAllCancelled addAllDue View
ORD-000002 addAllPaid addAllCancelled addAllDue View
ORD-000003 addAllPaid addAllCancelled addAllDue View
如果有阵列为佣金中没有值，用0代替它，否则它们添加以及基于所述顺序code显示它。我如何做到这一点？
If there is no value in the array for commission, replace it with 0, else add them and display it based on the order code. How do I achieve this ?
在code，我到目前为止已经试过： - >
The code that I have tried so far:->
<?php
$qu = "SELECT
c.*, o.*, acp.*, .*, a.*
FROM
customers c, orders o, affiliate_commission_payable acp, commission com, affiliates a
WHERE
a.AffiCode = '".$affiCode."'
AND
c.AffiCode = '".$affiCode."'
AND
c.CustEmailAdd = o.CustEmailAdd
AND
acp.CommId = com.commId
AND
com.OrderCode = o.OrderCode
AND
com.AffiCode = c.AffiCode";
$validate->Query($qu);
if ($validate->NumRows() >= 1) {
while ($rows = $validate->FetchAllDatas()) {
$commId = $rows["CommId"];
$orderCode = $rows["OrderCode"];
$orderDate = $rows["OrderDate"];
$arrCommissionStatus = explode(', ', $rows["ACP_PaymentStatus"]);
$prdCodes = explode(', ', $rows["ProdCode"] );
$arrAffiCommAmount = explode(', ', $rows["AffiCommAmount"]);
$ord = explode(', ', $rows["OrderCode"]);
$prdCodeAndCommStatus = array_combine($prdCodes, $arrCommissionStatus);
$arrCommAndStatus = array_combine($arrCommissionStatus, $arrAffiCommAmount);
$table .= "<tr>";
$table .= "<td>".$orderCode."</td>";
$table .= "<td>".$orderDate."</td>";
$table .= "<td>".count($prdCodes)."</td>";
foreach ($arrCommAndStatus as $key => $value) {
if ($value == 'Due') {
$totDueComm += $key;
} else {
$totDueComm = 0;
}
}
foreach ($arrCommAndStatus as $key => $value) {
if ($value == 'Cancelled') {
$totCancellComm += $key;
} else {
$totCancellComm = 0;
}
}
foreach ($arrCommAndStatus as $key => $value) {
if ($value == 'Paid') {
$totPaidComm += $key;
} else {
$totPaidComm = 0;
}
}
$table .= "<td>".number_format($totPaidComm, 2)."</td>";
$table .= "<td>".number_format($totCancellComm, 2)."</td>";
$table .= "<td>".number_format($totDueComm, 2)."</td>";
$table .= "<td>".number_format(array_sum($arrAffiCommAmount), 2)."</td>";
$table .= "<td><a href='//www.example.com/nbs/Affiliates/Commission.php?ord=".$orderCode."&id=".$commId."'>View</a></td>";
$table .= "</tr>";
}
}
更新1
我莫名其妙地试图把它做..这里是code，我不得不上面while循环中改变：
I have somehow tried to get it done.. Here's the code that I had to change inside the while loop above:
$strQ = "SELECT com.*, acp.* FROM commission com, affiliate_commission_payable acp WHERE com.AffiCode = '".$affiCode."' AND com.OrderCode = '".$orderCode."' AND com.CommId = acp.CommId";
$validate->Query($strQ);
if ($validate->NumRows() >= 1) {
while ($rows_strQ = $validate->FetchAllDatas()) {
$comAmt = explode(', ', $rows_strQ["AffiCommAmount"]);
$coStat = explode(', ', $rows_strQ["ACP_PaymentStatus"]);
$ts = array_combine( $comAmt, $coStat);
foreach ($ts as $key => $value) {
if (in_array($value, $sta) && $value == 'Due') {
$totDueComm += $key;
$totalDueCommission += $totDueComm;
}
}
}
}
但更新刚刚做它一阶，而不是所有的订单。我在哪里出了错？请帮助我。谢谢你。
But the update has just done it for 1st order and not all the orders. Where have I gone wrong ? Kindly help me out. Thanks.
更新2
我也总算是完成它。但有这一数额是越来越添加到previous的订单金额，然后显示量。例如，说我有一个卢比问题。 300订购1 和卢比。在订购2 ..因此，对于订购1 ，它会显示 RS 200。 300 和订购2 ，显示的金额为卢比。 500 。我想让它显示卢比。 200 ，而不是只500卢比我要如何解决这个问题？请帮我..再次感谢。
I have somehow managed it to get it done.. But there is a problem that the amount is getting added to the previous order amount and then the amount is displayed.. For example, Say I have Rs. 300 in Order 1 and Rs. 200 in Order 2.. So for Order 1, it will display Rs. 300 and for Order 2, the amount shown is Rs. 500. I want it to show Rs. 200 only and not Rs 500. How do I solve this ? Please help me.. Thanks once again.
下面是我迄今使用code：
Here's the code that I have used so far:
推荐答案
根据聊天，这里的解决方案：的http：// ideone.com/tXoWDk
Based on chat, here the solution: http://ideone.com/tXoWDk
我不知道理解你的数据库结构中的所有领域，但如果像你说的，要总结佣金每笔订单在数据库中，这里的如何做到这一点的例子：
I'm not sure of understanding all fields in your database structure, but if, as you said, want to sum commissions for each order in your database, here a sample of how to do that:
select
o.code, sum(c.amount) as total
from orders o
inner join com c on c.orderId = o.id
group by o.code
问题的关键是，这样做，在PHP也没用，因为MySQL能够处理它也没有任何进一步的处理，所以如果我简化结构是这样的：
The point is that doing that in PHP is useless as MySQL can handle it as well without any further processing, so if I simplify the structure like this:
mysql> select * from orders;
+----+------------+
| id | code |
+----+------------+
| 1 | ORDER-0001 |
| 2 | ORDER-0002 |
+----+------------+
mysql> select * from com;
+----+--------+---------+-----------+
| id | amount | orderId | status |
+----+--------+---------+-----------+
| 1 | 15 | 1 | DUE |
| 2 | 12 | 1 | DUE |
| 3 | 2 | 2 | CANCELLED |
| 4 | 23 | 2 | PAID |
| 5 | 3 | 1 | CANCELLED |
| 6 | 5 | 1 | PAID |
| 7 | 12 | 2 | CANCELLED |
+----+--------+---------+-----------+
mysql> select
-> o.code, c.status, sum(c.amount) as total
-> from orders o
-> inner join com c on c.orderId = o.id
-> group by c.status, o.code
-> order by o.code, c.status, c.amount;
+------------+-----------+-------+
| code | status | total |
+------------+-----------+-------+
| ORDER-0001 | CANCELLED | 3 |
| ORDER-0001 | DUE | 27 |
| ORDER-0001 | PAID | 5 |
| ORDER-0002 | CANCELLED | 14 |
| ORDER-0002 | PAID | 23 |
+------------+-----------+-------+
和的总和，只适用于以下到你的结果是：
and to sum the total, just apply the following to your result:
$ordersTotalCommissions = [];
// fetch your data
foreach ($result as $line) {
// initialize the 'order' group by putting 0 as a commission
if (!isset($ordersTotalCommissions[$line['code']])) {
$ordersTotalCommissions[$line['code']] = 0;
}
// sum each commission
$ordersTotalCommissions[$line['code']] += $line['total'];
}
print_r($ordersTotalCommissions);
告诉我，如果可以帮助您
Tell me if that helps you
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