麻烦来自多个领域的数据转换成一个阵列 [英] Trouble getting data from multiple fields into one array

问题描述

我有一个看起来像这样的形式：

I have a form that looks like this:

<form name="search" method="post" action="http://example.com/search3/">
Seach for: <input type="text" name="find[]" /> 
Search for stories by Type
<select name="find[]">
<option value="Fiction" selected>Fiction</option>
<option value="Non-Fiction">Non-Fiction</option>
<option value="Essay">Essay</option>
</select>
<input type="submit" name="search" value="Search" />
</form>

在php.search，我通过获取数据：

on php.search, I get the data by:

$input = array(
"find" => $_POST['find'],
);

这几乎是工作，但它并没有把结果查找数组中为止。相反，数据会成数组2的结果，可能是B / C我命名为每场找到[]。这里是后续代码var_dump：

It is almost working, except it doesn't put the results in the find array. Instead the data is going into the results in array2, probably b/c i named each field find[]. Here is the var_dump:

array(1) {
["find"]=>
array(2) {
[0]=>
string(5) "testing1"
[1]=>
string(7) "testing2"
}
}

我不知道为什么我离开查找阵列空白在这种情况下。

I'm not sure why i leaves the find array blank in this case.

如果我改变形式，以便这一发现[]的名称作为数组变得只是觉得，
然后我得到进入指定的数组中的数据发现像我想要的，但是，只有选择表格数据将被捕获。见的var_dump的结果，我怎么只得到一个结果，而不是两个：

If I change the form so the find[] names as arrays become just find, then I get the data to go into the array named find like i want, HOWEVER, only the select form data will be captured. See var_dump for results and how I only get one result instead of two:

array(1) {

["find"]=>
string(7) "testing2"

}

所以，问题是...
我怎样才能查找数组中捕获的输入，并选择数据？

SO THE QUESTION IS... How can I get the input AND select data captured in the find array?

推荐答案

在用方括号 [] 命名场，PHP会自动在<$ C嵌套数组$ C> $ _ POST （或 $ _ GET ）阵列。

When naming field using square brackets [], PHP automatically creates a nested array in the $_POST (or $_GET) array.

在你的情况，$输入['发现']的值有两个数字键的数组。

In your case, the value of $input['find'] is an array that has two numeric keys.

echo $input['find'][0];
echo $input['find'][1];

您可以假设指数0持有文本输入输入的值，该指数1持有该列表中选择的值。

You can assume that index 0 holds the value entered in text input, the index 1 holds the value selected in the list.

如果你跳过字段名称squre支架，浏览器将它们发送到服务器，如下所示：

If you skip the squre brackets in field names, browsers sends them to the server as follows:

find=value1&find=value2

PHP，关键在分析数据时，首先将值1 在找到，但当另一个找到键时，它只是会覆盖新的值2的previous值。

PHP, when parsing data, first stores the value1 under the key find, but when another find key occurs, it just overwrites the previous value with new value2.

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