回声变量中的字符串，从数据库getted [英] Echo a string with variable inside, getted from DB

问题描述

我从MySQL获得查询字符串，我已经将其打印到屏幕上。这个字符串，我需要打印一些变量太多。从数据库字符串可能是：

I get from a MySQL query a string and I've to print it to screen. Into this string, I need to print some variable too. The string from DB could be:

Finally, the team {$matchData['team_name']} have scored a point!

$ matchData ['TEAM_NAME'] 是本场比赛的计算期间使用数组，如果我做一个简单的

$matchData['team_name'] is an array used during the calculation of the match, and if I do a simple

echo $matchData['team_name'];

将打印球队的正确名称（BOSTON在这种情况下）。但是为什么，如果我回应来自DB getted字符串，回声打印：

Finally, the team {$matchData['team_name']} have scored a point!

而不是

Finally, the team BOSTON have scored a point!

我在哪里失败？

推荐答案

PHP似乎只是在简单的情况来处理字符串变量替换...的万无一失的方法，以确保它始终工作原理是利用串联，如：

PHP seems to handle variable substitution in strings only in the simpler cases... the foolproof way to make sure it always works is to use concatenation, like:

echo "Finally, the team ".$matchData['team_name']." have scored a point!";

在PHP手册页的确，虽然举这个例子：

The PHP man page does give this example though:

// You can also use arrays
$baz = array("value" => "foo");

echo "this is {$baz['value']} !"; // this is foo !

所以，你可能要仔细检查你对这种语法了。

So you might want to double check your syntax against that, too.

最后，echo使用可变长度的参数列表，所以你也可以这样写：

Finally, echo takes a parameter list of variable length so you can also write:

echo "Finally, the team ", $matchData['team_name'], " have scored a point!";

这篇关于回声变量中的字符串，从数据库getted的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！