c程序中出现错误“对gettid的未定义引用" [英] getting error in c program "undefined reference to gettid"

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本文介绍了c程序中出现错误“对gettid的未定义引用"的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

这是我的线程子例程...在这里,我创建了 4 个线程并将结构作为参数传递给线程子例程.

This is my thread sub routine... Here, I am creating 4 threads and passing structure as a argument to thread sub routine.

我正在尝试使用 getid() 函数打印线程 ID,

I am trying to print thread id with getid() function,

我收到错误消息,说未定义对 gettid() 的引用".

我已经添加了必要的头文件...

I have added necessary header files...

#include <pthread.h>
#include <stdio.h>
#include <sys/types.h>
#define ARRAYSIZE 17
#define NUMTHREADS 4

struct ThreadData {
        int start, stop;
        int* array; 
};

void* squarer(void* td) 
{
     struct ThreadData* data=(struct ThreadData*) td;

     int start=data->start;
     int stop=data->stop;
     int* array=data->array;
     int i;
     pid_t tid1;

     tid1 = gettid(); //error at this statement//`
     printf("tid : %d\n",tid1);

     for (i=start; i<stop; i++) {
         sleep(1);
         array[i]=i*i;
         printf("arr[%d] = [%d]\n",i,array[i]);
     } 
   return NULL;
}

int main(void) {
    int array[ARRAYSIZE];
    pthread_t thread[NUMTHREADS];
    struct ThreadData data[NUMTHREADS];
    int i;

    int tasksPerThread=(ARRAYSIZE+NUMTHREADS-1)/NUMTHREADS;

    for (i=0; i<NUMTHREADS; i++) {
            data[i].start=i*tasksPerThread;
            data[i].stop=(i+1)*tasksPerThread;
            data[i].array=array;
    }

    data[NUMTHREADS-1].stop=ARRAYSIZE;

    for (i=0; i<NUMTHREADS; i++) {
            pthread_create(&thread[i], NULL, squarer, &data[i]);
    }

    for (i=0; i<NUMTHREADS; i++) {
            pthread_join(thread[i], NULL);
    }

    for (i=0; i<ARRAYSIZE; i++) {
            printf("%d ", array[i]);
    }
    printf("\n");

    return 0;
}

推荐答案

尝试

#include <unistd.h>
#include <sys/syscall.h>

#ifdef SYS_gettid
pid_t tid = syscall(SYS_gettid);
#else
#error "SYS_gettid unavailable on this system"
#endif

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