合并两个对象并在冲突时覆盖值 [英] Merge two objects and overwrite the values if conflict

问题描述

我正在尝试合并两个对象并覆盖该过程中的值.

是否可以使用 underscore 执行以下操作?(我可以不使用下划线，我只是希望它简单)

var obj1 = {"你好":"xxx"赢":xxx"};var obj2 = {"你好":"zzz"};var obj3 = 合并(obj1，obj2)；/*{"你好":"zzz",赢":xxx"}*/

解决方案

你可以使用 Underscore 的扩展:

 var obj3 = _.extend({}, obj1, obj2);

第一个参数被修改，所以如果你不想修改obj1或obj2，只需传入{}.>

Vanilla JS: const obj3 = Object.assign({}, obj1, obj2);

更新:考虑现代 ES6 解决方案(参见其他答案)

I'm trying to merge two objects and overwrite the values in the process.

Is it possible with underscore to do the following? (I'm fine with not using underscore I just want it to be simple)

var obj1 = {
    "hello":"xxx"
    "win":"xxx"
};

var obj2 = {
    "hello":"zzz"
};

var obj3 = merge(obj1, obj2);

/*

{
    "hello":"zzz",
    "win":"xxx"
}

*/

解决方案

You could use Underscore's extend:

 var obj3 = _.extend({}, obj1, obj2);

The first argument is modified, so if you don't want to modify obj1 or obj2 just pass in {}.

Vanilla JS: const obj3 = Object.assign({}, obj1, obj2);

UPDATE: Consider modern ES6 solutions (see other answers)

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