比较两个相似的 XML 数据与 Java 中的无序元素/属性 [英] Comparing two similar XML data with unordered elements/attributes in Java

问题描述

我正在寻找一种可以比较两个 XML 数据的 API.我已经尝试过 XMLUnit 2，但找不到让它在我的示例中正常工作的方法.你能给我一个适合我需要的例子吗?

I'm looking for an API which compares two XML data. I've tried XMLUnit 2 but couldn't find a way to make it work properly with my example. Could you give me an example which works for my need?

我的第一个 XML 数据 xml1:

My first XML data xml1:

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<urlset xmlns="http://www.sitemap.org/schemas/sitemap/0.9">
    <url>
        <loc>a1/</loc>
        <lastmod>a2</lastmod>
    </url>
    <url>
        <loc>b1</loc>
        <lastmod>b2</lastmod>
    </url>
    <url>
        <loc>c1</loc>
        <lastmod>c2</lastmod>
    </url>
</urlset>

我的第二个 XML 数据 xml2:

My second XML data xml2:

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<urlset xmlns="http://www.sitemap.org/schemas/sitemap/0.9">
    <url><lastmod>b2</lastmod><loc>b1</loc></url>
    <url>
        <lastmod>c2</lastmod>
        <loc>c1</loc>
    </url>
    <url>
        <loc>a1/</loc>
        <lastmod>a2</lastmod>
    </url>
</urlset>

注意:

• 大小相同(这里有 3 个孩子)
• urlset 的子节点(url)不能排序
• url 的元素(loc 和 lastmod)可能无法排序
• 忽略空格

• Same size (here 3 children)
• urlset's child nodes (url) may not be ordered
• url's elements (loc and lastmod) may not be ordered
• White spaces are ignored

寻找返回 true 的 API，例如:

Looking for an API which returns true like:

XMLUtils.isSimilar(xml1, xml2);

我使用 XMLUnit 2 的失败尝试(尝试使用多个NodeMatcher"):

My unsuccessful attempts with XMLUnit 2 (tried with multiple "NodeMatcher"):

// Attempt with XmlAssert.assertThat:
XmlAssert.assertThat(xml1)
    .and(xml2)
    .ignoreChildNodesOrder()
    .ignoreWhitespace()
    .withNodeMatcher(new DefaultNodeMatcher(ElementSelectors.byNameAndText))
    .areSimilar();

// Attempt with Diff
Diff myDiff = DiffBuilder.compare(xml1)
    .withTest(xml2)
    .ignoreWhitespace()
    .checkForSimilar()
    .withNodeMatcher(new DefaultNodeMatcher(ElementSelectors.byNameAndText))
     .build();
myDiff.getDifferences();

推荐答案

你可以尝试如下

public class XMLUtils {
    private static DocumentBuilderFactory documentBuilderFactory;
    private static DocumentBuilder documentBuilder;
    private static TransformerFactory transformerFactory;
    private static Transformer transformer;
    private static Document emptyDoc;

    public XMLUtils() {
    }

    public XMLCompareResult compare(File expectedFile, File actualFile, boolean ignoreWhiteSpace) throws FileNotFoundException, SAXException, IOException {
        FileInputStream expInpStream = new FileInputStream(expectedFile);
        FileInputStream actualInpStream = new FileInputStream(actualFile);
        Diff myDiff = null;
        if (ignoreWhiteSpace) {
            myDiff = DiffBuilder.compare(expInpStream).withTest(actualInpStream).checkForSimilar().ignoreWhitespace().withNodeMatcher(new DefaultNodeMatcher(new ElementSelector[]{ElementSelectors.byNameAndAllAttributes})).build();
        } else {
            myDiff = DiffBuilder.compare(expInpStream).withTest(actualInpStream).checkForSimilar().withNodeMatcher(new DefaultNodeMatcher(new ElementSelector[]{ElementSelectors.byNameAndAllAttributes})).build();
        }

        XMLResultUtil xmlr = new XMLResultUtil();
        XMLCompareResult xs = xmlr.prepareXMLCompareResult(myDiff.getDifferences());
        return xs;
    }  

    static {
        try {
            documentBuilderFactory = DocumentBuilderFactory.newInstance();
            documentBuilder = documentBuilderFactory.newDocumentBuilder();
            transformerFactory = TransformerFactory.newInstance();
            transformer = transformerFactory.newTransformer();
            emptyDoc = documentBuilder.newDocument();
        } catch (ParserConfigurationException var1) {
            var1.printStackTrace();
        } catch (TransformerConfigurationException var2) {
            var2.printStackTrace();
        }

    }
}

我在这里复制了我们在我的项目中使用的方法.

I copying here a method we are using in my project.

你能试试吗，如果你遇到任何问题，请告诉我.我可以自己再试试.

Could you try it and let me know if you are facing any issue. I can try by myself again.

谢谢

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