如何解决双跳 [英] How to solve double jumping

问题描述

我遵循了Roll-A-Ball"的 Unity 教程，并添加了一些扩展.球现在可以跳跃了，但是每次跳跃的次数太多了；当我按下 SPACE 时，我一次只想要一次球.现在我可以按 3 次 SPACE，它会跳得越来越高.

I've followed the Unity tutorial for "Roll-A-Ball", and have added some extensions. The ball can now jump, but it jumps too many times each jump; I just want the ball once at a time when I press on SPACE. Now I can press on SPACE 3 times an it'll jump higher and higher.

  if (Input.GetKeyDown(KeyCode.Space))
        {
            Vector3 jump = new Vector3(0.0f, 150.0f, 0.0f);

            rb.AddForce(jump);
        } 

尝试稍微更改代码，但现在我只能跳一次(第一次)

Have tried changing the code a little bit, but now I can ONLY jump once (the first time)

private void textBox_KeyDown(object sender, KeyEventArgs e)
{
      if (Input.GetKeyDown(KeyCode.Space) && jump.y <= 0.0f)
    {
        jump.Set(0.0f, 150f, 0.0f);
        rb.AddForce(jump);

     }
    }

推荐答案

我找到了解决方案.解决方案是添加 OnCollisionEnter ，您可以在其中处理玩家与地面碰撞时会发生的情况.此外，我添加了一个计数器，当玩家跳跃时设置为 0，当他与地面碰撞时设置为 0.

I've found a solution. The solution is to add OnCollisionEnter where you can handle what will happen when the player collides with the ground. Furthermore I've added a counter which is set to 0 when the player jumps and 0 again when he collides with the ground.

计数器:

  if (Input.GetKeyDown(KeyCode.Space))
    {
        if (JumpCount < 1)
        {
            Vector3 jump = new Vector3(0.0f, 250.0f, 0.0f);
            rb.AddForce(jump);
            JumpCount++;
        } 
    }

这里的计数器设置为 0:

The counter is set to 0 here:

 void OnCollisionEnter(Collision other)
{
    JumpCount = 0;
}

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