用Unity实例化同一个类中同一个接口的两个对象 [英] Instatiate with Unity two objects of same interface in the same class

问题描述

我有一个案例，我需要为同一个接口实例化两个在同一个类中使用的不同实现.

I have a case where I need to instantiate for the same interface two different implementation that are both used in the same class.

public AutoMapperRegisterFactory(IRegisterAutoMapper registerAutoMapper , IRegisterAutoMapper registerAutoMapperMobile)
{
   m_RegisterAutoMapper = registerAutoMapper;
}

我将如何告诉 unity 第一个 IRegisterAutoMapper 应该是 RegisterAutoMapper 类型，第二个应该是 RegisterAutoMapperMobile 类型?

How would I go about of telling unity that the first IRegisterAutoMapper should be of type RegisterAutoMapper and the second of type RegisterAutoMapperMobile ?

推荐答案

您可以使用 IRegisterAutoMapper 的多个命名映射并结合一个 InjectionConstructor 来实现，该 InjectionConstructor 告诉 Unity 为每个参数使用哪些特定映射.

You can do it with multiple named mappings for IRegisterAutoMapper combined with an InjectionConstructor telling Unity what specific mappings to use for each argument.

IUnityContainer container = new UnityContainer()
    .RegisterType<IRegisterAutoMapper, RegisterAutoMapper>() //default
    .RegisterType<IRegisterAutoMapper, MobileRegisterAutoMapper>("Mobile")
    .RegisterType<AutoMapperRegisterFactory>(
        new InjectionConstructor(
            typeof(IRegisterAutoMapper), 
            new ResolvedParameter<IRegisterAutoMapper>("Mobile")));

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