给定开始和结束行号，从文件中获取一系列行 [英] Get a range of lines from a file given the start and end line numbers

问题描述

我需要从给定开始行号和结束行号的文件中提取一定数量的行.

I need to extract a set number of lines from a file given the start line number and end line number.

我怎样才能在 unix 下快速做到这一点(它实际上是 Solaris，所以 gnu 风格不可用).

How could I quickly do this under unix (it's actually Solaris so gnu flavour isn't available).

谢谢

推荐答案

打印第 6-10 行:

To print lines 6-10:

sed -n '6,10p' file

如果文件很大，并且结束行数比行数小，可以通过以下方式提高效率:

If the file is huge, and the end line number is small compared to the number of lines, you can make it more efficient by:

sed -n '10q;6,10p' file

从测试具有相当多行的文件:

From testing a file with a fairly large number of lines:

$ wc -l test.txt 
368048 test.txt
$ du -k test.txt 
24640    test.txt
$ time sed -n '10q;6,10p' test.txt >/dev/null
real   0m0.005s
user   0m0.001s
sys    0m0.003s
$ time sed -n '6,10p' test.txt >/dev/null
real   0m0.123s
user   0m0.092s
sys    0m0.030s

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