如何在unix脚本中检查某些字符串之间的字符串? [英] How to check for strings between certain strings in unix scripting?

查看:18
本文介绍了如何在unix脚本中检查某些字符串之间的字符串?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

字符串:

name@gmail.com

检查:

@
.com

我的代码

if [[ $word =~ "@" ]] 
then 
    if [[ $word =~ ".com" || $word =~ ".ca"  ]]

我的问题

name@.com

上面的例子通过了,这不是我想要的.如何检查@"和.com"之间的字符(1 个或多个)?

The above example gets passed, which is not what I want. How do I check for characters (1 or more) between "@" and ".com"?

推荐答案

您可以使用非常基本的正则表达式:

You can use a very very basic regex:

[[ $var =~ ^[a-z]+@[a-z]+\.[a-z]+$ ]]

它寻找一个完全像这样的字符串:

It looks for a string being exactly like this:

at least one a-z char
@
at least one a-z char
.
at least one a-z char

它可以根据您的需要变得复杂,例如参见使用 bash 脚本的电子邮件检查正则表达式.

It can get as complicated as you want, see for example Email check regular expression with bash script.

$ var="a@b.com"

$ [[ $var =~ ^[a-z]+@[a-z]+\.[a-z]+$ ]] && echo "kind of valid email"
kind of valid email

$ var="a@.com"
$ [[ $var =~ ^[a-z]+@[a-z]+\.[a-z]+$ ]] && echo "kind of valid email"
$

这篇关于如何在unix脚本中检查某些字符串之间的字符串?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆