/etc/passwd 中行的正则表达式验证 [英] Regex Verification of Line in /etc/passwd

问题描述

我需要验证/etc/passwd 文件是否有效，并且认为正则表达式是验证非注释行的好主意.我将如何验证如下一行:

root:*:0:0:系统管理员:/var/root:/bin/sh

经过研究，第 5 个字段(系统管理员)可以包含电子邮件和地址等其他数据，第二个字段可以包含除 : 之外的任何内容，最后 2 个字段是完整路径.

我将如何为此创建正则表达式的任何线索?

解决方案

类似的事情?

^(#.*|[az]*:[^:]*:[0-9]*:[0-9]*:[^:]*:/[^:]*:/[^:]*)$

(假设用户名由小写字母组成)

I need to verify an /etc/passwd file is valid, and thought regex would be a good idea to verify the lines that are not comments. How would I verify a line like:

root:*:0:0:System Administrator:/var/root:/bin/sh 

After some research, the 5th field (System administrator) can contain other data like email and address, the second field could contain anything but a :, the last 2 fields are full paths.

Any clues how I would create a regex expression for this?

解决方案

Something like this?

^(#.*|[a-z]*:[^:]*:[0-9]*:[0-9]*:[^:]*:/[^:]*:/[^:]*)$

(assuming that the username consists of lowercase letters)

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