在 Unix 中删除 ANSI 颜色转义的最佳方法 [英] Best way to remove ANSI color escapes in Unix

问题描述

我有一个 perl 程序，它的打印输出带有颜色.如果我重定向文件中的输出并在 vi 中打开它，我会看到颜色特殊字符.像这样的东西.

^[[31;43m而且这个也是红色 on_yellow ^[[0m

从输出文件中删除此颜色字符的最佳方法是什么?

谢谢

更新:

我试过这个正则表达式.它对我有用:

 cat -v a|head^[[30;41m这是黑色的_红色^[[0m^[[30;41m这也是黑色的_红色^[[0m^[[30;42m 这是黑色 on_green^[[0m^[[30;42m这也是黑色 on_green ^[[0m^[[30;43m这是黑色 on_yellow^[[0m^[[30;43m这也是黑色的_黄色的^[[0m^[[30;44m 这是黑色 on_blue^[[0m^[[30;44m这也是黑色 on_blue ^[[0m^[[30;45m 这是黑色 on_magenta^[[0m^[[30;45m这也是黑色的_洋红色^[[0m$ cat -v a|head|perl -lane 's/\^\[\[\d+(;\d+)*m//g;打印'这是黑色 on_red这也是黑色 on_red这是黑色 on_green这也是黑色 on_green这是黑色 on_yellow这也是黑色 on_yellow这是黑色 on_blue这也是黑色 on_blue这是黑色 on_magenta这也是黑色 on_magenta

解决方案

碰巧我刚好解决了这个问题，这就是我想出的正则表达式:

while (<>) {s/\e\[[\d;]*[a-zA-Z]//g;打印;}

我只是通过检查一些示例输出(特别是 grep --color=always ... 的输出)得出的，因此它可能无法涵盖您期望的所有转义.

根据本站信息，最后一个字符类可能会从 [a-zA-Z] 缩短为 [mK].

I have a perl progaram its prints output with color. if I rediect the output in the file and open it in vi I see color special character. something like this.

^[[31;43mAnd this is red on_yellow too^[[0m

What is the best way to remove this color character from the output file?

Thanks

Update:

I tried thid regex. it works for me:

 cat -v a|head
^[[30;41mThis is black on_red^[[0m
^[[30;41mAnd this is black on_red too^[[0m
^[[30;42mThis is black on_green^[[0m
^[[30;42mAnd this is black on_green too^[[0m
^[[30;43mThis is black on_yellow^[[0m
^[[30;43mAnd this is black on_yellow too^[[0m
^[[30;44mThis is black on_blue^[[0m
^[[30;44mAnd this is black on_blue too^[[0m
^[[30;45mThis is black on_magenta^[[0m
^[[30;45mAnd this is black on_magenta too^[[0m


$ cat -v a|head|perl -lane 's/\^\[\[\d+(;\d+)*m//g; print'
This is black on_red
And this is black on_red too
This is black on_green
And this is black on_green too
This is black on_yellow
And this is black on_yellow too
This is black on_blue
And this is black on_blue too
This is black on_magenta
And this is black on_magenta too

解决方案

Coincidentally I just had to solve this problem, and this is the regexp I came up with:

while (<>) {
    s/\e\[[\d;]*[a-zA-Z]//g;
    print;
}

I just derived this by examining some example output (in particular, the output of grep --color=always ...), so it may not cover all the escapes you expect.

According to the information on this site, the last character class could probably be shorten from [a-zA-Z] to just [mK].

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