咖啡脚本多维数组创建 [英] Coffee script multidimensional array creation

问题描述

所以我试图让一个多维数组中的CoffeeScript工作。我曾尝试与标准的Python列表COM prehension符号，这使得内部支架的字符串或东西。所以我不能做列表[0] [1]拿到1，我不是获取列表[0] [0] ='1,1'和列表[0] [1] =''

So I'm trying to get a multidimensional array to work in CoffeeScript. I have tried with standard Python list comprehension notation, that makes the inner bracket a string or something. so I can't do list[0][1] to get 1, I instead get list[0][0] = '1,1' and list[0][1] = ''

[[i, 1] for i in [1]]

使用类作为储存容器，以然后抓住x和y。这使不确定不确定，而不是1的后半部分。

Using a class as the storage container, to then grab x and y. Which gives 'undefined undefined', rather then '1 1' for the latter part.

class Position
    constructor:(@x,@y) ->

x = [new Position(i,1) for i in [1]]
for i in x
    alert i.x + ' ' + i.y#'undefined undefined'

i = new Position(1,1)
alert i.x + ' ' + i.y#'1 1'

能够使用点极其需要的清单，我无法找到一种方法，让他们的名单。我想preFER用一个简单的多维数组，但我不知道怎么办。

Being able to use a list of points is extremely needed and I cannot find a way to make a list of them. I would prefer to use a simple multidimensional array, but I don't know how.

推荐答案

您只需要使用括号，（），而不是方括号 [] 。

You just need to use parenthesis, (), instead of square brackets, [].

从REPL：

coffee> ([i, 1] for i in [1])
[ [ 1, 1 ] ]
coffee> [[i, 1] for i in [1]]
[ [ [ 1, 1 ] ] ]

您可以看到，使用方括号，你会在Python，提出一个额外的名单内的发电前pression。

you can see that using the square brackets, as you would in Python, puts the generating expression inside of an extra list.

这是因为括号（）实际上只是在CoffeeScript的那里，当你想除权pression分配给一个变​​量，所以：

This is because the parenthesis, () are actually only there in CoffeeScript for when you want to assign the expression to a variable, so:

coffee> a = ([i, 1] for i in [1])
[ [ 1, 1 ] ]
coffee> a[0][1]
1
coffee> b = [i, 1] for i in [1]
[ [ 1, 1 ] ]
coffee> b[0][1]
undefined

此外，请参阅 CoffeeScript的食谱。

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