将多个文本文件附加到单个文件中的脚本 [英] Script to append multiple text files into single file

问题描述

我是 Unix 新手，我需要写一个脚本.有人可以帮助我解决我在目录中有文件列表的要求，如果文件名中的字符串模式匹配，我想合并文件吗?

I am new to Unix , I need to write a script. Can someone help me with a requirement where I have list of files in a directory, I want to Merge the files if a pattern of string matches in filenames?

AAAL_555A_ORANGE1_F190404_D190408.TXT.freshfruits_20190422-115617       
AAAL_555A_ORANGE2_F190404_D190408.TXT.freshfruits_20190422-115617       
AAAL_555A_ORANGE3_F190404_D190408.TXT.freshfruits_20190422-115617       
AAAL_555A_ORANGE4_F190404_D190408.TXT.freshfruits_20190422-115617     
AAAL_555B_ORANGE5_F190404_D190408.TXT.freshfruits_20190422-115617       
AAAL_555B_Orange6_F190404_D190408.TXT.freshfruits_20180422-115617 

如果文件名的第二部分='555A'而第三部分由 ORANGE 组成，则所有 Oranges/555A 内容文件将合并为一个文件，文件名为 AAL_555a_Orange_date +"%Y%m%d".txt.

If second part of filename='555A' and third part consists of ORANGE then all Oranges/555A content files will merger into one file with filename as AAL_555a_Orange_date +"%Y%m%d".txt.

如果文件名的第二部分='555B'而第三部分由 ORANGE/555B 组成，则所有 Oranges 内容文件将合并为一个文件，文件名为 AAL_555b_Orange_date +"%Y%m%d".txt.

If second part of filename='555B' and third part consists of ORANGE/555B then all Oranges content files will merger into one file with filename as AAL_555b_Orange_date +"%Y%m%d".txt.

如果文件名的第二部分='555A'而第三部分由 MANGO 组成，那么所有 Mango 内容文件将合并为一个文件，文件名为 AAL_555a_Mango_date +"%Y%m%d".txt.

If second part of filename='555A' and third part consists of MANGO then all Mango content files will merger into one file with filename as AAL_555a_Mango_date +"%Y%m%d".txt.

请帮助..！

我知道以下命令可以将多个文件附加到一个 .但在这里我想根据文件名中存在的模式来做.

I know the below command to appended multiple files into one . But here i want to do based on patterns present in filename.

cat File1 file2 file3 >> final.txt

像这样

for i in *.TXT; do    
   while field separator='_' read -r str1 num str2 ; do    
     if [ "$str1" = "RTG" ]; then    

     fi         
   done     
done  

推荐答案

使用 Bash 变量替换.

脚本循环所有 AAAL 起始文件，将它们的名称存储到变量 $in 并使用变量替换来处理名称，直到只有第二和第三部分左(例如 AAAL_555A_ORANGE1_F190404.TXT -> 555A_ORANGE).

Script loops all the AAAL starting files, stores their names to variable, $in and uses variable substitutions to process the names until there are only the second and third parts left (for example AAAL_555A_ORANGE1_F190404.TXT -> 555A_ORANGE).

请参阅脚本中的注释以获取分步示例和链接文档以获取替换说明:

See the comments in the script for a step-by-step example and linked documentation for substitution explanation:

$ for in in AAAL*
  do                              # for example       AAAL_555A_ORANGE1_F190404.TXT
      out=${in#*_}                # remove AAAL_        -> 555A_ORANGE1_F190404.TXT
      out=${out%_*}               # remove _F190404.TXT -> 555A_ORANGE1
      out=${out%[0-9]}            # remove 1            -> 555A_ORANGE
      cat $in >> AAAI_$out.txt
  done
$ ls -1 AAAI*
AAAI_555A_MANGO.txt
AAAI_555A_ORANGE.txt
AAAI_555B_APPLE.txt
AAAI_555B_Orange.txt
AAAI_555B_ORANGE.txt

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