不兼容的C类错误？ [英] incompatible type C error?

问题描述

uint32 InterruptLatency;
uint8 measurements[32];
char buf[256];
int kernelinterrupt time()
{
fscanf(fp,"%lu", InterruptLatency);  // I am reading the data from kernel which is not shown here
measurements[17] = InterrupLatency;
buf = &measurements;            // I am getting error here as below

// after storing it in buffer I am  sending the data from but to another layer
}

错误：从类型UINT8（*）[32]

ERROR : incompatible type when assigning of type char[256] from type uint8 (*)[32]

可以有人帮助我如何解决这个问题？

could some one help me how to solve this ??

推荐答案

在c您不能分配数组。你必须明确地复制内存。​​

In C you cannot assign arrays. You have to copy the memory explicitly.

也许你想这样做：

memcpy(buf, measurements, sizeof(measurements));

但是你没有给什么你真正想做的事情的细节。

But you gave no details about what you actually want to do.

PS：您的的fscanf（）是错误的。它应该采取的变量，将持有的读取值的地址。

PS: Your fscanf() is wrong. It should take the address of the variable that will hold the read value.

如果你使用 uint32_t的你应该使用 SCNu32 的规范，从＆LT; inttypes.h＆GT; ，以确保你不打破东西：

And if you use uint32_t you should use the SCNu32 specification, from <inttypes.h>, to be sure that you do not break things:

fscanf(fp,"%"SCNu32, &InterruptLatency);

这篇关于不兼容的C类错误？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！