蟒蛇网址下载 [英] Python URL download

问题描述

下面的代码返回none.我该如何解决?我使用的是 Python 2.6.

The code below returns none. How can I fix it? I'm using Python 2.6.

import urllib

URL = "http://download.finance.yahoo.com/d/quotes.csv?s=%s&f=sl1t1v&e=.csv"
symbols = ('GGP', 'JPM', 'AIG', 'AMZN','GGP', 'JPM', 'AIG', 'AMZN')
#symbols = ('GGP')

def fetch_quote(symbols):
    url = URL % '+'.join(symbols)
    fp = urllib.urlopen(url)
    try:
        data = fp.read()
    finally:
        fp.close()

def main():
    data_fp = fetch_quote(symbols)
#    print data_fp
if __name__ =='__main__':
    main()

推荐答案

你必须从 fetch_quote 函数中显式地return data.像这样:

You have to explicitly return the data from fetch_quote function. Something like this:

def fetch_quote(symbols):
    url = URL % '+'.join(symbols)
    fp = urllib.urlopen(url)
    try:
        data = fp.read()
    finally:
        fp.close()
    return data # <======== Return

在没有显式返回语句的情况下，Python 返回 None，这就是您所看到的.

In the absence of an explicit return statement Python returns None which is what you are seeing.

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