使用 Python urllib 超时文件下载? [英] Timeout a file download with Python urllib?

查看:30
本文介绍了使用 Python urllib 超时文件下载?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

这里是 Python 初学者.如果该过程花费的时间超过 500 秒,我希望能够使我的视频文件下载超时.

Python beginner here. I want to be able to timeout my download of a video file if the process takes longer than 500 seconds.

import urllib
try:
   urllib.urlretrieve ("http://www.videoURL.mp4", "filename.mp4")
except Exception as e:
   print("error")

我如何修改我的代码来实现这一点?

How do I amend my code to make that happen?

推荐答案

更好的方法是使用 requests 以便您可以流式传输结果并轻松检查超时:

Better way is to use requests so you can stream the results and easily check for timeouts:

import requests

# Make the actual request, set the timeout for no data to 10 seconds and enable streaming responses so we don't have to keep the large files in memory
request = requests.get('http://www.videoURL.mp4', timeout=10, stream=True)

# Open the output file and make sure we write in binary mode
with open('filename.mp4', 'wb') as fh:
    # Walk through the request response in chunks of 1024 * 1024 bytes, so 1MiB
    for chunk in request.iter_content(1024 * 1024):
        # Write the chunk to the file
        fh.write(chunk)
        # Optionally we can check here if the download is taking too long

这篇关于使用 Python urllib 超时文件下载?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆