Python 3.4 url​​lib.request 错误 (http 403) [英] Python 3.4 urllib.request error (http 403)

问题描述

我正在尝试打开并解析一个 html 页面.在 python 2.7.8 中我没有问题:

I'm trying to open and parse a html page. In python 2.7.8 I have no problem:

import urllib
url = "https://ipdb.at/ip/66.196.116.112"
html = urllib.urlopen(url).read()

一切都很好.但是我想转移到 python 3.4，然后我收到 HTTP 错误 403(禁止).我的代码:

and everything is fine. However I want to move to python 3.4 and there I get HTTP error 403 (Forbidden). My code:

import urllib.request
html = urllib.request.urlopen(url) # same URL as before

File "C:\Python34\lib\urllib\request.py", line 153, in urlopen
return opener.open(url, data, timeout)
File "C:\Python34\lib\urllib\request.py", line 461, in open
response = meth(req, response)
File "C:\Python34\lib\urllib\request.py", line 574, in http_response
'http', request, response, code, msg, hdrs)
File "C:\Python34\lib\urllib\request.py", line 499, in error
return self._call_chain(*args)
File "C:\Python34\lib\urllib\request.py", line 433, in _call_chain
result = func(*args)
File "C:\Python34\lib\urllib\request.py", line 582, in http_error_default
raise HTTPError(req.full_url, code, msg, hdrs, fp)
urllib.error.HTTPError: HTTP Error 403: Forbidden

它适用于不使用 https 的其他 URL.

It work for other URLs which don't use https.

url = 'http://www.stopforumspam.com/ipcheck/212.91.188.166'

没问题.

推荐答案

网站似乎不喜欢 Python 3.x 的用户代理.

It seems like the site does not like the user agent of Python 3.x.

指定 User-Agent 将解决您的问题:

Specifying User-Agent will solve your problem:

import urllib.request
req = urllib.request.Request(url, headers={'User-Agent': 'Mozilla/5.0'})
html = urllib.request.urlopen(req).read()

注意 Python 2.x urllib 版本也收到 403 状态，但与 Python 2.x urllib2 和 Python 3.x urllib 不同，它不会引发异常.

NOTE Python 2.x urllib version also receives 403 status, but unlike Python 2.x urllib2 and Python 3.x urllib, it does not raise the exception.

您可以通过以下代码确认:

You can confirm that by following code:

print(urllib.urlopen(url).getcode())  # => 403

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