从python中的用户输入获取二维数组模式 [英] Getting 2-d array pattern from user inputs in python

问题描述

我想给用户输入模式作为input1: 00,01,10,11和另一个输入作为input2:0.1,0.2,0.24,0.5这些输入我从这两个输入中一一给出替代值.为了提供用户输入，我正在使用:input = int(raw_input()).但我想要的输出应该在单独的二维数组中作为 [[0,0],[0,1],[1,0],[1,1]] 和 [[0.1],[0.2],[0.24],[0.5]] 请给我一个好主意.

I want to give the user input pattern as input1: 00,01,10,11 and another input as input2: 0.1,0.2,0.24,0.5 and these inputs I am giving alternate value as one by one from these two inputs. For giving user input I am using: input = int(raw_input()). But my desired output should be in separate 2-d array as [[0,0],[0,1],[1,0],[1,1]] and [[0.1],[0.2],[0.24],[0.5]] please give me good idea for this.

推荐答案

您可以使用 str.split 将输入的字符串转换为子字符串列表:

You can use str.split to convert the string input into a list of substrings:

"0.1,0.2".split(",") == ["0.1", "0.2"]

和 map 应用一些对这些子串的处理规则；在您的第二种情况下，这是转换为 float:

map(float, "0.1,0.2".split(",")) == [0.1, 0.2]

您的第一个示例(二进制字符串到整数列表)将需要 map 的自定义函数，例如:

Your first example (binary strings to lists of integers) will require a custom function for map, for example:

map(lambda s: map(int, s), "001,010".split(",")) == [[0, 0, 1], [0, 1, 0]]

请注意，在 Python 3.x 中 map 是一个迭代器，因此您可能需要将其显式转换为 list.

Note that in Python 3.x map is an iterator, so you may need to explicitly convert it to a list.

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