读取TXT文件和存储整数到一个数组 [英] Read integers from txt file and storing into an array

问题描述

我有问题读，从文本文件中存储的整数。我使用的，所以我想这样做没有列表中的int数组。我得到一个输入匹配例外，我不知道我应该怎么去纠正这个问题。从还包括字符串读取的文本文件。

 公共静态整数[] readFileReturnIntegers（字符串文件名）{
     整数[]数组=新的整数[1000];
     INT I = 0;
    //连接到文件
     档案文件=新的文件（文件名）;
     扫描仪INPUTFILE = NULL;
     尝试{
        INPUTFILE =新的扫描仪（文件）;
     }
     //如果没有文件中发现错误消息
        赶上（FileNotFoundException异常除外）{
           的System.out.println（找不到文件！）;
        }
    //如果连接，读取文件
     如果（INPUTFILE！= NULL）{
        System.out.print（文件中\\整数数目，
              +文件名+\\= \\ n）;
        //通过阵列文件整数和储存环
        而（inputFile.hasNext（））{
           数组[我] = inputFile.nextInt（）;
           我++;
        }
        inputFile.close（）;
     }
     返回数组;
  }
 

解决方案

您可以使用这样的事情（跳过任何非INT（S）），并应关闭扫描仪！

  //如果连接，读取文件
如果（INPUTFILE！= NULL）{
  System.out.print（文件中\\整数数目，
      +文件名+\\= \\ n）;
  //通过阵列文件整数和储存环
  尝试{
    而（inputFile.hasNext（））{
      如果（inputFile.hasNextInt（））{
        数组[我] = inputFile.nextInt（）;
        我++;
      }其他{
        inputFile.next（）;
      }
    }
  } {最后
    inputFile.close（）;
  }
  //我想你想打印。
  的System.out.println（ⅰ）;
  为（中间体V = 0; V族I; v ++）{
    System.out.printf（数组内容[％d =％d个\\ N，V阵列[V]）;
  }
}
 

I'm having issues reading and storing only integers from a text file. I'm using a int array so I want to do this without list. I'm getting a input mismatch exception, and I don't know how I should go about correcting that issue. The text files being read from also include strings.

  public static Integer[] readFileReturnIntegers(String filename) {
     Integer[] array = new Integer[1000];
     int i = 0;
    //connect to the file
     File file = new File(filename);
     Scanner inputFile = null;
     try {
        inputFile = new Scanner(file);
     } 
     //If file not found-error message
        catch (FileNotFoundException Exception) {
           System.out.println("File not found!");
        }
    //if connected, read file
     if(inputFile != null){         
        System.out.print("number of integers in file \"" 
              + filename + "\" = \n");
        //loop through file for integers and store in array     
        while (inputFile.hasNext()) {
           array[i] = inputFile.nextInt();
           i++;
        }
        inputFile.close();
     }
     return array;
  }

解决方案

You might use something like this (to skip over any non-int(s)), and you should close your Scanner!

// if connected, read file
if (inputFile != null) {
  System.out.print("number of integers in file \""
      + filename + "\" = \n");
  // loop through file for integers and store in array
  try {
    while (inputFile.hasNext()) {
      if (inputFile.hasNextInt()) {
        array[i] = inputFile.nextInt();
        i++;
      } else {
        inputFile.next();
      }
    }
  } finally {
    inputFile.close();
  }
  // I think you wanted to print it.
  System.out.println(i);
  for (int v = 0; v < i; v++) {
    System.out.printf("array[%d] = %d\n", v, array[v]);
  }
}

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