转换.string文件格式转化成PHP数组格式 [英] converting .string file format into php array format

问题描述

希望你在做文件

因此​​，这里是我的问题，我有一个用于translation.Please一个xyz.s​​tring文件中找到以下文件的一小部分。

So here is my question i have a xyz.string file that is used for translation.Please find the a small part of file below.

/* name for an item that is duplicated in the UI, based on the original name */
"%@ (Copy)" = "%@ (kopi)";

/* display name for a book page template that is the first page of that section */
"%@ (First)" = "%@ (Første)";

/* display name for a book page template that represents a hardcover cover. the second argument is the cover type. */
"%@ (Hardcover, %@)" = "%1$@ (Hard innbinding, %2$@)";

/* display name for a book page template that represents a softcover cover. the second argument is the cover type. */
"%@ (Softcover, %@)" = "%1$@ (myk innbinding, %2$@)";

我要翻译即转换成一个PHP数组像

i want to convert the translation i.e in a php array like

array(
array{
"%@ (First)"=>"%@ (Første)"
},
array
{
"@ (Hardcover, %@)"=>"%1$@ (Hard innbinding, %2$@)"
}
)

和所以指定盘符，格式不是强制性的，但它应该是，我可以解决方法。

and so on.The format that is specified is not mandatory but it should be something that i can workaround with.

以下是文件格式的规范

• 键 - 值对与平等字符分隔（=）和
  （;）。

• key-value pairs are delimited with the equal character (=), and terminated by a semicolon (;).

键和值是用双引号（）

占位外观可以是：％.2f，％D，％1 $ S（普通前pression为
占位符：/％[。\\ D |]的 \\ $ 的\\ D * [DSF] {1} \\ B + /）

place-holders look can be: %.2f, %d, %1$s (regular expression for placeholders: /%[\d|.]\$\d*[dsf]{1}\b+/)

注释开始在该行的开始和跨越整条生产线
或者多行

comments start at the beginning of the line and span the whole line or multiple lines

单行注释开始用双斜杠（//）多行
评论被包围在/ * * /

single-line comments start with double slashes (//) multi-line comments are enclosed in /* */

除非有任何评论被分配给下一个键 - 值对
空行

a comment is assigned to the next key-value pair unless there are any blank lines in between

我知道这可以通过preG_MATCH_ALL可以实现，但我不能够创建一个漂亮的定期EX pression

下面是我的code

$str=file_get_contents($_FILES['string']['tmp_name']);
preg_match_all("|(\".+\"\;)|s",preg_quote($str),$match);
echo "<pre/>";print_r($match);die;

file_get_content后，我得到确切的字符串是继

the exact string i am getting after file_get_content is following

/* name for an item that is duplicated in the UI, based on the original name */ "%@ (Copy)" = "%@ (kopi)"; /* display name for a book page template that is the first page of that section */ "%@ (First)" = "%@ (Første)"; /* display name for a book page template that represents a hardcover cover. the second argument is the cover type. */ "%@ (Hardcover, %@)" = "%1$@ (Hard innbinding, %2$@)";

如果任何人都可以帮我在这这将是pciated多少AP $ P $

If anyone can help me in this it will be much appreciated

谢谢
瑞安

推荐答案

主，正则表达式：

"([^"]+)"\s*=\s*"([^"]+)";

说明的

Explanations:

"([^"]+)"     # Every thing between double quotes
\s*=\s*       # Equal sign preceded or followed by any number of spaces
"([^"]+)";    # Again every thing between double quotes that ends to a ;

PHP code：

PHP code:

$text = file_get_contents($_FILES['string']['tmp_name']);
preg_match_all('#"([^"]+)"\s*=\s*"([^"]+)";#', $text, $match);
$translate = array_combine($match[1], $match[2]);
print_r($translate);

在输出作为您的示例文本将是：

The output for your sample text will be:

Array
(
    [%@ (Copy)] => %@ (kopi)
    [%@ (First)] => %@ (Første)
    [%@ (Hardcover, %@)] => %1$@ (Hard innbinding, %2$@)
    [%@ (Softcover, %@)] => %1$@ (myk innbinding, %2$@)
)

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