基于previous查询结果的PHP / MySQL插入多条记录 [英] PHP / MySQL Insert Multiple Records Based On Previous Query Results

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问题描述

我试图制定通知到我的网站的某些功能进行更改的premium成员PHP脚本,但我不知道如何将多个记录添加到通知表。我拥有的是:

I'm trying to develop a PHP script that notifies premium members of changes made to certain features of my website but I'm not sure how to add the multiple records to the notifications table. What I have is:

    $get_pro_sql = "SELECT id FROM members WHERE pro = '1'";
    $get_pro_res = mysqli_query($con, $get_pro_sql);

while($row = mysqli_fetch_assoc($get_pro_res){
    $memberid = $row["id"];
}
$message = "My New Message";
foreach($row){



    $insert_note_sql = "INSERT INTO notes(id, recipient, message, ..., ...) VALUES('', 'Member_Id__Returned_From_Previous_Query', '$message')";
    $insert_note_res = mysqli_query($con, $insert_note_sql);
    // Inserts 5 Records

如何可以做到这一点任何想法?

Any ideas on how this can be achieved?

推荐答案

您可以通过这个使用子查询来插入多行。

You could this by using a sub query to insert multiple rows.

其实你可以做到这样的:

Actually you can achieve it like this:

INSERT INTO Results (People, names )
   SELECT d.id, 'Henry'
   FROM Names f
   JOIN People d ON d.id  = f.id

在子查询中,您可以选择要插入的实际值。

In the subquery you can select the actual values to be inserted.

<一个href=\"http://stackoverflow.com/questions/9422529/mysql-how-do-you-insert-into-a-table-with-a-select-subquery-returning-multiple-r\">More关于这一主题这里

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