在一个阵列取决于它们的值替换元素 [英] Replace elements in an array depending on their value

问题描述

我有内部嵌套数组的数组。每个阵列都具有它有一个五位数作为它的值称为CBSA的元素。在不同的阵列，我有五位数字作为键，对应于它们的值作为其值。欲环路直通嵌套阵列和替换与来自第二阵列的相应值的五位值。例如：

  $阵列=阵列（阵列（CBSA =＆GT; 12345），
               阵列（CBSA =＆GT; 98765），
               阵列（CBSA =＆GT; 56789））;
 

而在另一个数组我有这样的：

  $数组2 =阵列（12345 =＆gt;中乔治·华盛顿
                56789 =＆GT; 巴拉克奥巴马，
                98765 =＆GT; 托马斯·杰斐逊）;
 

我想找到的值每个嵌套阵列中，并与所述第二阵列中的相应的字符串代替它。

，使得第一阵列将变成：

  $阵列=阵列（阵列（CBSA =＆gt;中乔治·华盛顿），
               阵列（CBSA =＆gt;中托马斯·杰斐逊），
               阵列（CBSA =＆gt;中美国总统奥巴马））;
 

解决方案

最好的办法是遍历你的第一个数组，然后就分配给它从第二个数组对应的值......像这样

  $结果=阵列（）;的foreach（$数组$关键=＆GT; $ CBSA）{
    如果（使用isset（$数组2 [$ CBSA ['CBSA']））{
        $阵列[$关键] ['CBSA'] =
        $结果[] =阵列（'CBSA'=＆GT; $数组2 [$ CBSA ['CBSA']）;
    }
}
 

作为使用初始code和上述环的完整工作示例，这得到所需的输出：

 ＆LT; PHP$阵列=阵列（阵列（'CBSA'=＆GT; 12345），
               阵列（'CBSA'=＆GT; 98765），
               阵列（'CBSA'=＆GT; 56789））;$数组2 =阵列（12345 =＆gt;中乔治·华盛顿
                56789 =＆GT; 巴拉克奥巴马，
                98765 =＆GT; 托马斯·杰斐逊）;$结果=阵列（）;的foreach（$数组$关键=＆GT; $ CBSA）{
    如果（使用isset（$数组2 [$ CBSA ['CBSA']））{
        $结果[] =阵列（'CBSA'=＆GT; $数组2 [$ CBSA ['CBSA']）;
    }
}
回声（'＆LT; pre＆GT;'）;
的print_r（$结果）;
 

I have an array with nested arrays inside. Each array has an element called CBSA which has a five digit number as its value. In a different array, I have the five digit number as keys, and the values corresponding to them as their values. I want to loop thru the nested array and replace the five digit value with their corresponding values from the second array. For example:

$array = array(array(CBSA => 12345),
               array(CBSA => 98765),
               array(CBSA => 56789));

And in another array I have this:

$array2 = array(12345 => "George Washington",
                56789=> "Barack Obama",
                98765=> "Thomas Jefferson");

I want to find the values in each nested array and replace it with the corresponding string in the second array.

So that the first array will become:

$array = array(array(CBSA=>"George Washington"), 
               array(CBSA=>"Thomas Jefferson"), 
               array(CBSA => "Barack Obama"));

解决方案

The best way would be to loop through your first array, then just assign it the corresponding value from the second array... something like this

$results = array();

foreach($array as $key => $cbsa) {
    if (isset($array2[$cbsa['CBSA']])) {
        $array[$key]['CBSA'] = 
        $results[] = array('CBSA' => $array2[$cbsa['CBSA']]);
    }
}

As a full working example using your initial code, and the above loop, this gives the desired output:

<?php

$array = array(array('CBSA' => 12345),
               array('CBSA' => 98765),
               array('CBSA' => 56789));

$array2 = array(12345 => "George Washington",
                56789=> "Barack Obama",
                98765=> "Thomas Jefferson");

$results = array();

foreach($array as $key => $cbsa) {
    if (isset($array2[$cbsa['CBSA']])) {
        $results[] = array('CBSA' => $array2[$cbsa['CBSA']]);
    }
}
echo('<pre>');
print_r($results);

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