存储在Java中的多个值，而无需使用数组 [英] Storing multiple values in Java without using arrays

问题描述

5次拿用户的输入，将它们存储在一个变量，并在最后显示所有5个值。我如何在Java中做到这一点？如果不使用数组，集合或数据库。只有像字符串单个变量和 INT 。

Take user input for 5 times, store them in a variable and display all 5 values in last. How can I do this in Java? Without using arrays, collections or database. Only single variable like String and int.

输出应该是这样的。

https://drive.google.com/file/d/ 0B1OL94dWwAF4cDVyWG91SVZjRk0 /看法？PLI = 1

推荐答案

这似乎是一个不必要的无用功，但我离题...

This seems like a needless exercise in futility, but I digress...

如果你想将它们存储在一个单一的字符串，可以做到像这样：

If you want to store them in a single string, you can do it like so:

Scanner in = new Scanner(System.in); 

String storageString = "";

while(in.hasNext()){
  storageString += in.next() + ";";
}

如果你再输入富酒吧巴兹 storageString将包含 foo的;酒吧;巴兹; 。 （ in.next（）读取输入的字符串的空间，而 in.hasNext（）在返回false该行的末尾）

if you then input foo bar baz storageString will contain foo;bar;baz;. (in.next() will read the input strings to the spaces, and in.hasNext() returns false at the end of the line)

随着越来越多的字符串被输入时，它们被附加到storageString变量。要检索的字符串，可以使用的 String.split（字符串正则表达式） 。使用这像这样完成的：

As more strings are input, they are appended to the storageString variable. To retrieve the strings, you can use String.split(String regex). Using this is done like so:

String[] strings = storageString.split(";");

在字符串此处检索从storageString变量上面应该有值数组 [富，酒吧，巴兹 ] 。

the strings array which is retrieved here from the storageString variable above should have the value ["foo", "bar", "baz"].

我希望这有助于。使用字符串作为存储，因为JVM创建一个新的对象，每一个字符串追加到它的时间不是最佳的。为了解决这个问题，使用的StringBuilder 。

I hope this helps. Using a string as storage is not optimal because JVM creates a new object every time a string is appended onto it. To get around this, use StringBuilder.

*编辑：我原本说的字符串值阵列将 [富，酒吧，巴兹 ] 。这是错误的。 javadoc的国家，因此尾随空字符串不包含所得数组中。

* I originally had said the value of the strings array would be ["foo", "bar", "baz", ""]. This is wrong. The javadoc states 'Trailing empty strings are therefore not included in the resulting array'.

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