如何在字符串中包含尚未定义的变量?PHP [英] How do I include a yet to be defined variable inside a string? PHP

问题描述

为了执行更少的数据库查询和代码的清晰性，我想在字符串中包含一个尚未定义的变量.稍后在页面中，将声明变量并打印和评估字符串.我该怎么做?

For sake of performing less database queries and for clarity of code, I'd like include a yet to be defined variable inside a string. Later in the page, the variable will be declared and the string printed and evaluated. How do i do this?

$str="This $variable is delicious";

$array=array("Apple","Pineapple","Strawberry");

foreach($array as $variable)
{
  print "$str";
}

推荐答案

您可以使用 printf()(或 sprintf() 如果不想回显的话):

You can use printf() (or sprintf() if you don't want to echo it):

$str = 'This %s is delicious';

foreach ($array as $variable) {
    printf($str, $variable);
}

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