删除重复的数组项 [英] remove duplicated array item

问题描述

  VAR ARR = [吊灯，大女孩惊魂，烧页，人质，直取刀，针眼， 公平游戏，弹性的心，自由的动物，火相约汽油，玻璃纸，一袭黑衣，吊灯，弹性的心，吊灯，吊灯，弹性的心，弹性的心，大女孩惊魂，大女孩惊魂]; $。每个（ARR，功能（我，OBJ）{
的console.log（OBJ）;
}）;
 

我如何确保我的数组是独一无二的？

解决方案

通过的 阵列＃过滤器（） 并临时对象。

\r

\r

VAR ARR = [吊灯，大女孩惊魂，烧页，眼针的状况，人质，直取刀，公平游戏，弹性的心，自由的动物，火相约汽油，玻璃纸，披着黑，吊灯，弹性的心，吊灯，吊灯，弹性的心，弹性的心，大女孩惊魂，大女孩惊魂]\r
    独特= arr.filter（函数（）{\r
        如果（！这[一]）{\r
            该[A] =真;\r
            返回true;\r
        }\r
    }，{}）;\r
    \r
的document.write（'＆LT; pre＆GT;'+ JSON.stringify（独特，0,4）+'＆LT; / pre＆GT;'）;

\r

\r

\r

var arr = ["Chandelier", "Big Girls Cry", "Burn the Pages", "Eye of the Needle", "Hostage", "Straight for the Knife", "Fair Game", "Elastic Heart", "Free the Animal", "Fire Meet Gasoline", "Cellophane", "Dressed In Black", "Chandelier", "Elastic Heart", "Chandelier", "Chandelier", "Elastic Heart", "Elastic Heart", "Big Girls Cry", "Big Girls Cry"];

 $.each(arr, function(i,obj){
console.log(obj);
});

How can I make sure my array is unique?

解决方案

With Array#filter() and a temporary object.

var arr = ["Chandelier", "Big Girls Cry", "Burn the Pages", "Eye of the Needle", "Hostage", "Straight for the Knife", "Fair Game", "Elastic Heart", "Free the Animal", "Fire Meet Gasoline", "Cellophane", "Dressed In Black", "Chandelier", "Elastic Heart", "Chandelier", "Chandelier", "Elastic Heart", "Elastic Heart", "Big Girls Cry", "Big Girls Cry"],
    unique = arr.filter(function (a) {
        if (!this[a]) {
            this[a] = true;
            return true;
        }
    }, {});    
    
document.write('<pre>' + JSON.stringify(unique, 0, 4) + '</pre>');

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