如何打印在同一行上所有的数组元素？ [英] How do I print all array elements on the same line?

问题描述

我不得不删除所有code。什么我寻找是如何的sprintf数组的所有元素在同一直线上。

I had to delete all the code. What I' looking is how to sprintf all elements of an array in the same line.

该显示器具有2行，我需要打印阵列10,24,32,40,51，.....第一线
                         和10,51 .....第二行

The display has 2 lines, I need to print the array 10,24,32,40,51, .....first line and 10,51 .....second line

推荐答案

样品

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

char *join(int n, const int array[n], const char *format, const char *sep){
    if(!format)
        format = "%d";
    if(!sep)
        sep = ", ";
    size_t len = strlen(sep)*(n-1)+1;//+1 for EOS
    int i;
    for(i=0;i<n;++i)
        len += snprintf(NULL, 0, format, array[i]);
    char *result = malloc(len);
    if(!result)return NULL;
    size_t pos = 0;
    for(i=0;i<n;++i){
        pos += sprintf(result + pos, format, array[i]);
        if(i != n-1)
            pos += sprintf(result + pos, "%s", sep);
    }
    return result;
}

int main (void){
    int array[][5]={{10,24,32,40,51},{10,1,99,77,88}};
    int row_size = sizeof(array)/sizeof(array[0]);
    int col_size = sizeof(array[0])/sizeof(int);
    char *join_str;
    int i;
    for(i=0;i<row_size;++i){
        char *join_str = join(col_size, array[i], "%2d", ", ");
        printf("%s\n", join_str);
        free(join_str);
    }
    return 0;
}

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