从数组中删除最后一个元素 [英] Remove last element from array

问题描述

如何从 VB.NET 中的数组中删除最后一个元素.我需要拆分街道和门牌号.

How to remove the last element from an array in VB.NET. I need to split the street and housenumber.

街道

1. 在空格上分割地址
2. 删除最后一个元素(代码中缺失)
3. 加入数组

数字

1. 在空格上分割地址
2. 获取最后一个元素

我的代码:

'split address
Dim addressArray() As String = args.Content.Split(" ")

'remove last element and return the joined array
Return String.Join(" ", addressArray.Remove(addressArray.Length() - 1))

推荐答案

    Dim foo() As String = "This is a test".Split(New Char() {" "c}, StringSplitOptions.RemoveEmptyEntries)
    Array.Resize(foo, foo.Length - 1)
    Dim s As String = String.Join(" ", foo)

或使用列表

    Dim foo As New List(Of String)
    foo.AddRange("This is a test".Split(New Char() {" "c}, StringSplitOptions.RemoveEmptyEntries))
    foo.RemoveAt(foo.Count - 1)
    Dim s As String = String.Join(" ", foo)

至于使用LINQ和性能，自己判断

As far as using LINQ and performance, judge for yourself

Public Class Form1

    'to LINQ or not to LINQ
    'judge for yourself

    Dim stpw As New Stopwatch

    Private Sub Button1_Click(sender As System.Object, _
                              e As System.EventArgs) Handles Button1.Click

        Dim ipsumA() As String = New String() {"Lorem", "ipsum", "dolor", "sit", _
                                               "amet", "consectetur", "adipisicing", _
                                               "elit", "sed", "do", "eiusmod", _
                                               "tempor", "incididunt", "ut", "labore", _
                                               "et", "dolore", "magna", "aliqua", "Ut", _
                                               "enim", "ad", "minim", "veniam", "quis", _
                                               "nostrud", "exercitation", "ullamco", _
                                               "laboris", "nisi", "ut", "aliquip", "ex", _
                                               "ea", "commodo", "consequat", "Duis", "aute", _
                                               "irure", "dolor", "in", "reprehenderit", "in", _
                                               "voluptate", "velit", "esse", "cillum", "dolore", _
                                               "eu", "fugiat", "nulla", "pariatur", "Excepteur", _
                                               "sint", "occaecat", "cupidatat", "non", "proident", _
                                               "sunt", "in", "culpa", "qui", "officia", "deserunt", _
                                               "mollit", "anim", "id", "est", "laborum"}

        Const tries As Integer = 100000
        Debug.WriteLine("")

        stpw.Reset()
        stpw.Start()
        For x As Integer = 1 To tries
            Dim s As String = arrayTake(ipsumA)
        Next
        stpw.Stop()
        Debug.WriteLine(stpw.ElapsedTicks.ToString)

        stpw.Reset()
        stpw.Start()
        For x As Integer = 1 To tries
            Dim s As String = arrayRsz(ipsumA)
        Next
        stpw.Stop()
        Debug.WriteLine(stpw.ElapsedTicks.ToString)

    End Sub

    Private Function arrayRsz(test As String()) As String
        Array.Resize(test, test.Length - 1)
        Return String.Join(" ", test)
    End Function

    Private Function arrayTake(test As String()) As String
        Return String.Join(" ", test.Take(test.Length - 1))
    End Function
End Class

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