从数组创建动态变量 [英] Create dynamic Variables from an Array

问题描述

好的，所以我想使用数组中的名称将动态变量创建为整数.这是我迄今为止尝试过的:

Ok, so i want to create dynamic Variables as Integer using the names from an Array. This is what I've tried so far:

Dim subjects as Array {"Math", "English", "German"} 'Three example names
Dim subjectsInt as New Dictionary(Of Integer) 'Throws error: Not enough arguments
Dim i as Integer

For i = 0 to 2
    subjectsInt(subjects(i)) = 0 ' Trying to create a variable with the name of entry number i of the Array & and the starting value 0

    Do 
        Console.WriteLine(subjects(1) & ": ")
        Dim input As String = Console.ReadLine()
        subjectsInt = CInt(input)
    Loop While subjectsInt = 0 Or subjectsInt > 100
Next i

最后我想要这样的结果:

in the end I want a result like this:

Math = 10       'random values between 1 and 100
English = 40
German = 90

我希望我的问题足够清楚，提前致谢:)

I hope my question is clear enough, thanks in advance :)

推荐答案

你说得对，没有足够的论据.一本字典，更具体地说是 Dictionary(Of TKey, TValue)，接受键类型的参数和将要使用的值类型.

You're quite right that there's not enough arguments. A dictionary, more specifically a Dictionary(Of TKey, TValue), takes an argument for the type of key and the type of value it is going to use.

如果您希望它使用您的字符串进行查找，您必须将第一个类型设为 String:

As you want it to use your strings for lookup you would have to make the first type a String:

Dim subjectsInt As New Dictionary(Of String, Integer)

这将使您能够通过执行以下操作来访问值:

This will make you able to access the values by doing:

subjectsInt(<your string here>)

'Example:
subjectsInt("Math")
subjectsInt(subjects(0)) 'The first string (which is "Math") from the 'subjects' array.

虽然您必须确保先添加密钥，但您只能添加一次:

Though you must be sure to add the key first, but you may only add it once:

subjectsInt.Add("Math", <your initial value here>)

'You may use strings any way you can access them, for example:
subjectsInt.Add(subjects(0), <your initial value here>)
subjectsInt.Add(subjects(i), <your initial value here>)
'etc...

那么你应该能够根据需要获取/设置它:

Then you should just be able to get/set it as you wanted:

subjectsInt(subjects(i)) = CInt(input)

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