有人能帮我解决这个错误“OleDbException 未处理"吗? [英] can anybody help me solve this error "OleDbException was unhandled"?

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问题描述

这部分代码是让讲师发布咨询时间表,不幸的是我遇到了另一个错误,如标题所示,在有人可以帮我解决这个错误NullReferenceException 未处理"吗?,并且该错误可能已解决.现在,我的问题是当我单击发布按钮时,这就像将所有标签(具有表单中显示的颜色)保存到访问文件中,并且这些标签已声明为(石灰 = 可用,红色 = 不可用).

This part of the code is to let lecturer publish consultation schedule, unfortunately i experienced another error as shown in title, after done asking a question at Can anybody help me to solve this error "NullReferenceException was unhandled"? ,and that error is probably resolved. Now, my problem is when i clicked on the publish button which is like saving all the labels(that has the color lime as shown in the form) to an access file, and those labels already declared as(lime = available, red = unavailable).

这是表格

错误在 Dim f As Integer = cmd.ExecuteNonQuery()

The error is at Dim f As Integer = cmd.ExecuteNonQuery()

    Public Class ConsultationSchedule

Private Sub publishbutton_Click(sender As Object, e As EventArgs) Handles publishbutton.Click
    Dim label As String = "Label"

    Dim time1 As String = vbNull
    Dim time2 As String = vbNull
    Dim time3 As String = vbNull
    Dim time4 As String = vbNull
    Dim time5 As String = vbNull

    Dim day1 As String = vbNull
    Dim day2 As String = vbNull
    Dim day3 As String = vbNull
    Dim day4 As String = vbNull
    Dim day5 As String = vbNull

    Dim available1 As String = vbNull
    Dim available2 As String = vbNull
    Dim available3 As String = vbNull
    Dim available4 As String = vbNull
    Dim available5 As String = vbNull

    For i = 11 To 15
        time1 = Label7.Text

        For k = 16 To 20
            time2 = Label8.Text

            For t = 21 To 25
                time3 = Label9.Text

                For u = 26 To 30
                    time4 = Label10.Text

                    For bg = 33 To 37
                        time5 = Label32.Text

                    Next
                Next
            Next
        Next
    Next

    For i = 11 To 37
        If (i = 11) Then
            day1 = Label2.Text
            If Not Me.Controls(label & i.ToString) Is Nothing Then
                If (Me.Controls(label & i.ToString).BackColor = Color.Lime) Then
                    available1 = "Available"
                Else
                    available1 = "Unavailable"
                End If
            End If

        ElseIf (i = 16) Then
            day1 = Label2.Text
            If Not Me.Controls(label & i.ToString) Is Nothing Then
                If (Me.Controls(label & i.ToString).BackColor = Color.Lime) Then
                    available2 = "Available"
                Else
                    available2 = "Unavailable"
                End If
            End If

        ElseIf (i = 21) Then
            day1 = Label2.Text
            If Not Me.Controls(label & i.ToString) Is Nothing Then
                If (Me.Controls(label & i.ToString).BackColor = Color.Lime) Then
                    available3 = "Available"
                Else
                    available3 = "Unavailable"
                End If
            End If

        ElseIf (i = 26) Then
            day1 = Label2.Text
            If Not Me.Controls(label & i.ToString) Is Nothing Then
                If (Me.Controls(label & i.ToString).BackColor = Color.Lime) Then
                    available4 = "Available"
                Else
                    available4 = "Unavailable"
                End If
            End If

        ElseIf (i = 33) Then
            day1 = Label2.Text
            If Not Me.Controls(label & i.ToString) Is Nothing Then
                If (Me.Controls(label & i.ToString).BackColor = Color.Lime) Then
                    available5 = "Available"
                Else
                    available5 = "Unavailable"
                End If
            End If
        End If
    Next
    For ht = 11 To 37
        If (ht = 11) Then
            day1 = Label2.Text
        ElseIf (ht = 16) Then
            day1 = Label2.Text
        ElseIf (ht = 21) Then
            day1 = Label2.Text
        ElseIf (ht = 26) Then
            day1 = Label2.Text
        ElseIf (ht = 33) Then
            day1 = Label2.Text
        End If
    Next
    For k = 11 To 37
        If (k = 12) Then
            day2 = Label3.Text
        ElseIf (k = 17) Then
            day2 = Label3.Text
        ElseIf (k = 22) Then
            day2 = Label3.Text
        ElseIf (k = 27) Then
            day2 = Label3.Text
        ElseIf (k = 34) Then
            day2 = Label3.Text
        End If
    Next
    For t = 11 To 37
        If (t = 13) Then
            day3 = Label4.Text
        ElseIf (t = 18) Then
            day3 = Label4.Text
        ElseIf (t = 23) Then
            day3 = Label4.Text
        ElseIf (t = 28) Then
            day3 = Label4.Text
        ElseIf (t = 35) Then
            day3 = Label4.Text
        End If
    Next
    For u = 11 To 37
        If (u = 14) Then
            day4 = Label5.Text
        ElseIf (u = 19) Then
            day4 = Label5.Text
        ElseIf (u = 24) Then
            day4 = Label5.Text
        ElseIf (u = 29) Then
            day4 = Label5.Text
        ElseIf (u = 36) Then
            day4 = Label5.Text
        End If
    Next
    For y = 11 To 37
        If (y = 15) Then
            day5 = Label6.Text
        ElseIf (y = 20) Then
            day5 = Label6.Text
        ElseIf (y = 25) Then
            day5 = Label6.Text
        ElseIf (y = 30) Then
            day5 = Label6.Text
        ElseIf (y = 37) Then
            day5 = Label6.Text
        End If
    Next

    Dim sql As String
    Dim sql2 As String
    Dim sql3 As String
    Dim sql4 As String
    Dim sql5 As String

    Dim cmd As OleDbCommand
    Dim cmd2 As OleDbCommand
    Dim cmd3 As OleDbCommand
    Dim cmd4 As OleDbCommand
    Dim cmd5 As OleDbCommand

    Dim conn = New OleDbConnection("Provider=Microsoft.ACE.OLEDB.12.0;Data Source=scheduledatabase.accdb;Persist Security Info=False;")
    sql = "INSERT INTO consultationschedule([Time], weekDay, Available)VALUES(@time1,@day1,@available1)"
    sql2 = "INSERT INTO consultationschedule([Time], weekDay, Available)VALUES(@time2,@day2,@available2)"
    sql3 = "INSERT INTO consultationschedule([Time], weekDay, Available)VALUES(@time3,@day3,@available3)"
    sql4 = "INSERT INTO consultationschedule([Time], weekDay, Available)VALUES(@time4,@day4,@available4)"
    sql5 = "INSERT INTO consultationschedule([Time], weekDay, Available)VALUES(@time5,@day5,@available5)"

    Using (conn)
        conn.Open()
        cmd = New OleDbCommand(sql, conn)
        cmd.Parameters.Add(New OleDbParameter("@Time", time1))
        cmd.Parameters.Add(New OleDbParameter("@weekDay", day1))
        cmd.Parameters.Add(New OleDbParameter("@Available", available1))
        cmd2 = New OleDbCommand(sql2, conn)
        cmd2.Parameters.Add(New OleDbParameter("@Time", time2))
        cmd2.Parameters.Add(New OleDbParameter("@weekDay", day2))
        cmd2.Parameters.Add(New OleDbParameter("@Available", available2))
        cmd3 = New OleDbCommand(sql3, conn)
        cmd3.Parameters.Add(New OleDbParameter("@Time", time3))
        cmd3.Parameters.Add(New OleDbParameter("@weekDay", day3))
        cmd3.Parameters.Add(New OleDbParameter("@Available", available3))
        cmd4 = New OleDbCommand(sql4, conn)
        cmd4.Parameters.Add(New OleDbParameter("@Time", time4))
        cmd4.Parameters.Add(New OleDbParameter("@weekDay", day4))
        cmd4.Parameters.Add(New OleDbParameter("@Available", available4))
        cmd5 = New OleDbCommand(sql5, conn)
        cmd5.Parameters.Add(New OleDbParameter("@Time", time5))
        cmd5.Parameters.Add(New OleDbParameter("@weekDay", day5))
        cmd5.Parameters.Add(New OleDbParameter("@Available", available5))

        Dim f As Integer = cmd.ExecuteNonQuery()
        If (f >= 1) Then
            ToolStrip1.Text += f.ToString & " record added successfully"
        Else
            ToolStrip1.Text += "Unable to add record"
        End If
    End Using
End Sub

推荐答案

我建议你创建一个新的创建记录的方法:

I suggest you create a new method for creating a record:

 Private Sub AddRecords(ByVal time As String, ByVal day As String, ByVal available As String)

        Dim sql As String
        Dim cmd As OleDbCommand

        Dim conn = New OleDbConnection("Provider=Microsoft.ACE.OLEDB.12.0;Data Source=scheduledatabase.accdb;Persist Security Info=False;")
        sql = "INSERT INTO consultationschedule(Time, weekDay, Available)VALUES(@Time,@weekDay,@Available)"

        Using (conn)
            conn.Open
            cmd = New OleDbCommand(sql, conn)
            cmd.Parameters.AddWithValue("@Time", time)
            cmd.Parameters.AddWithValue("@weekDay", day)
            cmd.Parameters.AddWithValue("@Available", available)
            Dim f As Integer = cmd.ExecuteNonQuery()
            If (f >= 1) Then
                ToolStrip1.Text += f.ToString & " record added successfully"
            Else
                ToolStrip1.Text += "Unable to add record"

            End If
            MessageBox.Show("User Widrawed", "Widrawed", MessageBoxButtons.OK, MessageBoxIcon.Information)
        End Using
    End Sub

之后就可以调用添加记录的方法了

After that you could call the method for adding records

AddRecords(time1, day1, available1)
AddRecords(time2, day2, available2)
AddRecords(time3, day3, available3)
AddRecords(time4, day4, available4)
AddRecords(time5, day5, available5)

这篇关于有人能帮我解决这个错误“OleDbException 未处理"吗?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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