在 Xaml 中单击按钮时更改网格的可见性 [英] Change Visibility of Grid on Button Click in Xaml

问题描述

我试图找到某种方法，当单击按钮(菜单)时，它会使用 XAML 中的触发器 更改网格(子菜单)的可见性.我是在 vb.net 中实现的，但我想知道在 XAML 中是否更容易实现?

I am trying to find some way to when a button (Menu) is clicked, it changes the visibility of a Grid (Submenu) with a Trigger in XAML. I made it in vb.net but I wonder if it's easier to do in XAML?

Private Sub ShowSubmenu(SubmenuSettings e As Grid)
        Dim bk As Integer = VisualTreeHelper.GetChildrenCount(MainGrid)
        For i = 0 To bk - 1
            Dim g As Object = VisualTreeHelper.GetChild(MainGrid, i)
            If TypeOf g Is Grid Then g.Visibility = Visibility.Hidden
        Next
        SubmenuSettings.Visibility = Visibility.Visible
    End Sub

Private Sub Visibility(sender As Object)
        If sender Is btn1 Then
            ShowSubmenu(pdm1)
        End If
End Sub

推荐答案

您可以使用 ToggleButton 代替 Button，这个想法是根据 切换按钮.

You can use ToggleButton instead of Button, the idea is to switch Grid Visibility based on IsChecked Property of a ToggleButton.

<Grid  Height="100" Width="100" Background="Green">
   <Grid.Style>
      <Style TargetType="Grid">
          <Setter Property="Visibility" Value="Collapsed"/>
          <Style.Triggers>
             <DataTrigger Binding="{Binding IsChecked,ElementName=btnFirst}" Value="True">
                 <Setter Property="Visibility" Value="Visible"/>
              </DataTrigger>
          </Style.Triggers>
       </Style>
   </Grid.Style>
</Grid>

 <ToggleButton x:Name="btnFirst" Content="BtnFirst" Height="100" Width="100" />

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