r - 根据第一个向量重新排序第二个向量 [英] r - reorder second vector according to first

问题描述

正在寻找执行以下操作的解决方案:

有两个向量:

a <- c(2,1,3,4,7,6,5,9,8,10)
b <- c(3,2,1,6,5,4,7,8,9,10)

我想创建第三个向量，它给出向量 b 需要重新排序的顺序，使其与 a 的顺序相同.在这种情况下，我想得到:

I would like to create a third vector that would give the order in which vector b needs to be reordered for it to be in the same order as a. In this case I would like to get:

c <- c(2,3,1,6,7,4,5,9,8,10)

这样:

> b[c] == a
[1] TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE

这个问题不涉及a和b是双向量的情况，这就是为什么下面的问题也被问到r - 根据第一个双向量重新排序第二个双向量

This question does not refer to cases in which a and b are double vectors, which is why the following question is also asked r - reorder second double vector according to first double vector

推荐答案

我们可以只使用 'a' 作为索引

We can just use 'a' as index

c1 <- b[a]
b[c1] == a
#[1] TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE

如果 'a' 中的值不是整数，即 numeric double

If the values in 'a' are not integer i.e. numeric double

b[order(a)]

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