密码正则表达式与分6个字符，至少有一个字母和一个数字，可能包含特殊字符 [英] Password REGEX with min 6 chars, at least one letter and one number and may contain special characters

问题描述

我需要一个正规的前pression与条件：

I need a regular expression with condition:

• 分6个字符，最多50个字符


• 必须包含1个字母


• 必须包含1号


• 可以包含特殊字符，如@＃$％^＆安培;！*（）_ +

目前我有模式：（？！^ [0-9] * $）（？！^ [A-ZA-Z] * $）^（[A-ZA-Z0-9 ] {6,50}）$

Currently I have pattern: (?!^[0-9]*$)(?!^[a-zA-Z]*$)^([a-zA-Z0-9]{6,50})$

但它不允许的特殊字符，没有任何人有一个良好的正则表达式是什么？

However it doesn't allow special characters, does anybody have a good regex for that?

感谢

推荐答案

也许一个正则表达式可以使用，但是这使得它很难给予其排除他们不跟随用户的反馈。像这样的更传统的方法给你的反馈，你可以在UI使用来告诉是不是遇到什么PWD规则的用户：

Perhaps a single regex could be used, but that makes it hard to give the user feedback for which rule they aren't following. A more traditional approach like this gives you feedback that you can use in the UI to tell the user what pwd rule is not being met:

function checkPwd(str) {
    if (str.length < 6) {
        return("too_short");
    } else if (str.length > 50) {
        return("too_long");
    } else if (str.search(/\d/) == -1) {
        return("no_num");
    } else if (str.search(/[a-zA-Z]/) == -1) {
        return("no_letter");
    } else if (str.search(/[^a-zA-Z0-9\!\@\#\$\%\^\&\*\(\)\_\+]/) != -1) {
        return("bad_char");
    }
    return("ok");
}

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