vim:删除多行的前 2 个空格 [英] vim: delete the first 2 spaces for multiple lines

问题描述

使用 VIM 删除每行前 2 个空格的最简单方法是什么?基本上它对每一行重复2x".

What's the easiest way to delete the first 2 spaces for each line using VIM? Basically it's repeating "2x" for each line.

澄清:这里的假设是前 2 个字符是空格.所以问题是关于对多行一起做缩进.

Clarification: here the assumption is the first 2 characters are spaces. So the question is about doing indentation for multiple lines together.

推荐答案

更多选项.您可以决定哪种方法是最简单的方法".

Some more options. You can decided which is the "easiest way".

删除每行的前 2 个字符:

:%normal 2x

删除每行的前 2 个字符，仅当它们是空格时:

:%s/^  /

注意最后一个斜杠是可选的，只有在这里才能看到两个空格.没有斜线，只有 7 个字符，包括 :.

Note that the last slash is optional, and is only here so that you can see the two spaces. Without the slash, it's only 7 characters, including the :.

将每一行的缩进向左移动:

:%normal <<

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