执行代码 MSB6006 时出错 "CL.exeexecuted with code 2 [英] Error while executing code MSB6006 "CL.exeexecuted with code 2

问题描述

在 Visual Studio 2019 上执行代码时出现以下错误MSB6006"CL.exe" 以代码 2 退出

I am getting the following error while executing code on Visual Studio 2019 MSB6006"CL.exe" exited with code 2

#include<stdio.h>
#include<conio.h>

int main()
{
int a, b, c,x;
x = a / (b - c);

printf("\n Enter values of a,b and c");
scanf_s("%d%d%d", &a, &b, &c);
printf("\n The value of x is %d", x);
return 0;

}

推荐答案

您的语句顺序已关闭.
首先为 a、b 和 c 赋值.
只有在计算中使用这些值之后.

Your order of statements is off.
First assign values to a, b, and c.
Only after use those values in calculations.

#include <stdio.h>

int main(void) {
    int a, b, c, x;
    // x = a / (b - c); // NOPE! a, b, and c have no valid values

    printf("Enter values of a, b and c\n");
    scanf("%d%d%d", &a, &b, &c);
    x = a / (b - c);    // calculation moved here; a, b, and c (hopefully) have valid values now
    printf("The value of x is %d\n", x);
    return 0;
}

注意:要检查scanf()的返回值，以确保a、b和c 具有有效值.

Note: the return value of scanf() should be checked to be sure all of a, b, and c have valid values.

if (scanf("%d%d%d", &a, &b, &c) != 3) /* error */;

^{注2:我对你的代码做了一点改动:去掉了非标准的，改变了大部分'\n' 为了更加面向行，替换了可选的 scanf_s(此功能可能并非在所有 C11/C18 实现中都存在).}

^{Note 2: I changed your code a little bit: removed non-standard <conio.h>, changed the placing of most '\n' to be more line-oriented, replaced the optional scanf_s (this function may not exist in all C11/C18 implementations).}

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