通过 Axios 接收的列表中的 Vue2 搜索 [英] Vue2 Search in List received via Axios

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本文介绍了通过 Axios 接收的列表中的 Vue2 搜索的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

由于过滤比在 Vue 1 中复杂得多,我有一个问题.

这是我的组件,其中显示了绵羊列表,其中包含搜索/过滤名称或家庭的选项.但我不知道如何实现这一点.

<ul><li v-for="绵羊中的羊"><!-- 也尝试过:'sheep in filtersSheeps'-->{{sheep.name }} ({{sheep.type }}/{{sheep.family }} )<脚本>从 'axios' 导入 axios;导出默认{数据() {返回 {羊:[],搜索: '',};},安装(){this.getSheeps();}方法: {getSheeps() {var self = this;const url = '/api/sheeps';axios.get(url).then(function(response) {self.sheeps = response.data;});},},计算:{过滤的羊:函数(){var self = this;返回 this.sheeps.filter(function(item) {返回 item.family.toLowerCase().indexOf(self.search.toLowerCase()) >-1})}}}}

我认为它需要 v-for 中的计算方法 filteredSheeps,但也不是这样.然后直接报错:TypeError: null is not an object (evaluating 'item.family.toLowerCase')"

解决方案

这里有一个计算,可以保护您免受 family 和/或 name 不在的情况人口稠密.

filteredSheeps: function() {让 searchTerm = (this.search || "").toLowerCase()返回 this.sheeps.filter(function(item) {let family = (item.family || "").toLowerCase()let name = (item.name || "").toLowerCase()返回 family.indexOf(searchTerm) >-1 ||name.indexOf(searchTerm) >-1})}

还有一个工作示例.

console.clear()const 羊 = [{名称:百合",类型:杜泊",家庭:家庭 1"},{名称:乔",类型:美利奴",家庭:家庭 2"},{name: "Bob", type: "Dorper", family: null},]新的 Vue({el: "#app",数据:{羊:[],搜索:空},计算:{过滤的羊:函数(){让 searchTerm = (this.search || "").toLowerCase()返回 this.sheeps.filter(function(item) {let family = (item.family || "").toLowerCase()let name = (item.name || "").toLowerCase()返回 family.indexOf(searchTerm) >-1 ||name.indexOf(searchTerm) >-1})}},创建(){setTimeout(() => this.sheeps = 羊,500)}})

<script src="https://unpkg.com/vue@2.4.2"></script><div id="应用程序"><input type="search" v-model="search" placeholder="Search for Name OR Family"/><ul><li v-for="过滤羊中的羊">{{sheep.name }} ({{sheep.type }}/{{sheep.family }} )

since filtering is way more complex then in Vue 1, I have a question.

This is my Component, where a list of Sheeps is shown with the option to search/filter on Name or Family. But I can't figure out how to achieve this.

<input type="search" v-model="search" placeholder="Search for Name OR Family" />
<ul>
    <li v-for="sheep in sheeps"> <!-- Tried also: 'sheep in filteredSheeps' -->
        {{ sheep.name }} ({{ sheep.type }}/{{ sheep.family }} )
    </li>
</ul>
<script>
import axios from 'axios';
export default {
    data() {
            return {
                sheeps: [],
                search: '',
            };
        },
        mounted() {
            this.getSheeps();
        }
        methods: {
            getSheeps() {
                var self = this;
                const url = '/api/sheeps';
                axios.get(url).then(function(response) {
                    self.sheeps = response.data;
                });
            },
        },
        computed: {
            filteredSheeps: function() {
                var self = this;
                return this.sheeps.filter(function(item) {
                    return item.family.toLowerCase().indexOf(self.search.toLowerCase()) > -1
                })
            }
        }
    }
}
</script>

I thought that it needed the computed method filteredSheeps in the v-for, but that's not it either. Getting an error directly then: TypeError: null is not an object (evaluating 'item.family.toLowerCase')"

解决方案

Here is a computed that will protect you from cases where the family and/or name is not populated.

filteredSheeps: function() {
  let searchTerm = (this.search || "").toLowerCase()
  return this.sheeps.filter(function(item) {
    let family = (item.family || "").toLowerCase() 
    let name = (item.name || "").toLowerCase()
    return family.indexOf(searchTerm) > -1 || name.indexOf(searchTerm) > -1
  })
}

And a working example.

console.clear()

const sheeps = [
  {name: "Lily", type: "Dorper", family: "Family 1"},
  {name: "Joe", type: "Merino", family: "Family 2"},
  {name: "Bob", type: "Dorper", family: null},
]

new Vue({
  el: "#app",
  data:{
    sheeps:[],
    search: null
  },
  computed: {
    filteredSheeps: function() {
      let searchTerm = (this.search || "").toLowerCase()
      return this.sheeps.filter(function(item) {
        let family = (item.family || "").toLowerCase() 
        let name = (item.name || "").toLowerCase()
        return family.indexOf(searchTerm) > -1 || name.indexOf(searchTerm) > -1
      })
    }
  },
  created(){
    setTimeout(() => this.sheeps = sheeps, 500)
  }
})

<script src="https://unpkg.com/vue@2.4.2"></script>
<div id="app">
<input type="search" v-model="search" placeholder="Search for Name OR Family" />
<ul>
    <li v-for="sheep in filteredSheeps"> 
        {{ sheep.name }} ({{ sheep.type }}/{{ sheep.family }} )
    </li>
</ul>
</div>

这篇关于通过 Axios 接收的列表中的 Vue2 搜索的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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