spring mvc 如何绕过 *.html 文件的 DispatcherServlet? [英] spring mvc how to bypass DispatcherServlet for *.html files?
本文介绍了spring mvc 如何绕过 *.html 文件的 DispatcherServlet?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
web.xml 片段
<!-- Handles all requests into the application -->
<servlet>
<servlet-name>Spring MVC Dispatcher Servlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/app-config.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>Spring MVC Dispatcher Servlet</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
它工作正常,但我不想让 Dispatcher Servlet 处理 *.html 请求.我该怎么做?谢谢.
It works fine but I'd like to NOT let the Dispatcher Servlet handle *.html requests. How do I I do that? Thanks.
推荐答案
将其映射到更具体的 url-pattern
.
Map it on a more specific url-pattern
.
<servlet-mapping>
<servlet-name>Spring MVC Dispatcher Servlet</servlet-name>
<url-pattern>/spring/*</url-pattern>
</servlet-mapping>
创建一个映射在/*
上的Filter
.
<filter-mapping>
<filter-name>Your Dispatcher Filter</filter-name>
<url-pattern>/*</url-pattern>
<filter-mapping>
在 doFilter()
方法中执行以下操作.
Which does the following in doFilter()
method.
String uri = ((HttpServletRequest) request).getRequestURI();
if (uri.endsWith(".html")) {
chain.doFilter(request, response); // Just let it go (assuming that files are in real not placed in a /spring folder!)
} else {
request.getRequestDispatcher("/spring" + uri).forward(request, response); // Pass to Spring dispatcher servlet.
}
这篇关于spring mvc 如何绕过 *.html 文件的 DispatcherServlet?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文