websockets“方案https无效"，但我实际上是在尝试使用https [英] websockets "scheme https is invalid", but i'm actually trying to use https

问题描述

我正在使用:https://pypi.python.org/pypi/websocket-客户

尝试将 python 2.7 websockets 客户端连接到实际使用 https 而不是 ws 或 wss 的 URL，但我收到以下错误.无论如何，我可以解决这个问题吗?请注意，我没有创建这个 websockets 服务器，所以我无法控制它是否符合 ws 或 wss 标准.

Trying to connect a python 2.7 websockets client to a URL which actually uses https and not ws or wss, but i'm getting the following error. Anyway I can get around this? Please note that I did not create this websockets server so I have no control over making it conform to ws or wss standards.

错误:

方案 https 无效

scheme https is invalid

Python 代码如下:

import websocket
import thread
import time

def on_message(ws, message):
    print(message)

def on_error(ws, error):
    print(error)

def on_close(ws):
    print("### closed ###")

def on_open(ws):
    def run(*args):
        for i in range(3):
            time.sleep(1)
            ws.send("Hello %d" % i)
        time.sleep(1)
        ws.close()
        print("thread terminating...")
    thread.start_new_thread(run, ())


if __name__ == "__main__":
    websocket.enableTrace(True)
    ws = websocket.WebSocketApp("https://MYURL",
                              on_message = on_message,
                              on_error = on_error,
                              on_close = on_close)
    ws.on_open = on_open
    ws.run_forever()

我知道我可以连接到这个 websocket URL，因为以下 javascript 代码有效.

I know that I can connect to this websocket URL because the following javascript code works.

Javascript 代码如下:

const io = require('socket.io-client');

var socket = io.connect('https://MYURL', { transports: ['websocket'] });
socket.on('connect', () => {
  console.log('socket connected');
  getMarket();
});

socket.on('disconnect', () => {
  console.log('socket disconnected');
});

getMarket = () => {
  socket.emit('getMarket', {});

  socket.once('market', (market) => {
    console.log("stuff", market)
  });
}

我尝试修改 websocket-client 的源代码.去/Python/2.7/site-packages/websocket/_url.py的websocket-client的代码，修改如下代码:

I tried modifying the source code for websocket-client. Went to websocket-client's code at /Python/2.7/site-packages/websocket/_url.py and modified the following code:

is_secure = False
if scheme == "ws":
    if not port:
        port = 80
elif scheme == "wss":
    is_secure = True
    if not port:
        port = 443
else:
    pass
    #raise ValueError("!scheme %s is invalid" % scheme)

但是现在当我运行它时，我得到另一个错误

But now when I run it, I get another error

[Errno 49] 无法分配请求的地址

[Errno 49] Can't assign requested address

推荐答案

我也遇到了同样的情况，发了一个问题这里

I also got into the same situation and posted a question here

没有任何答案，我尝试按照您的步骤编辑 _url.py，它对我有用.这是我编辑 _url.py 的尝试:

Without any answer, I tried to follow your step by editing _url.py and it works for me. Here is my attempt in editing the _url.py:

def parse_url(url):
    """
    parse url and the result is tuple of
    (hostname, port, resource path and the flag of secure mode)

    url: url string.
    """
    if ":" not in url:
        raise ValueError("url is invalid")

    scheme, url = url.split(":", 1)

    parsed = urlparse(url, scheme="ws")
    if parsed.hostname:
        hostname = parsed.hostname
    else:
        raise ValueError("hostname is invalid")
    port = 0
    if parsed.port:
        port = parsed.port

    is_secure = False
    if scheme == "ws":
        if not port:
            port = 80
    elif scheme == "wss":
        is_secure = True
        if not port:
            port = 443
    else:
        if scheme == "https":
            is_secure = True
            if not port:
                port = 443
        else:
            raise ValueError("scheme %s is invalid" % scheme)

    if parsed.path:
        resource = parsed.path
    else:
        resource = "/"

    if parsed.query:
        resource += "?" + parsed.query

    return hostname, port, resource, is_secure

这篇关于websockets“方案https无效"，但我实际上是在尝试使用https的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！