如何在长按中从网络视图中获取 URL? [英] How to get URL from web view in long click?

问题描述

我有一个网页视图，我想在用户长按链接时获取 URL.我知道我可以做到这一点:

I have a web view that I want to get the URL when the user long clicks on links. I know I can do this:

// Register the context menu for web view
registerForContextMenu(webView);

还有:

 @Override
 public void onCreateContextMenu(@NonNull ContextMenu menu, @NonNull View v, ContextMenu.ContextMenuInfo menuInfo) {
    super.onCreateContextMenu(menu, v, menuInfo);

    final WebView.HitTestResult result = webView.getHitTestResult();
    Log.i("url is ===" , "result.getExtra()")

 }

但是这样，在诸如 Google 之类的搜索引擎中，不会返回 URL.这是我长按谷歌搜索结果时的日志:

But this way, In some search engines like Google, Not be return a URL. This is my log when I long clicked on google search results:

数据:图像/PNG; BASE64，iVBORw0KGgoAAAANSUhEUgAAABAAAAAQCAYAAAAf8/9hAAAA + klEQVR4AWMgBnwr4pRloAR8KuA89KmAK4V8A/LZ1YGGvPiQy65MtCaQjR8LuDxh/M8FXNlAQ078D2VgJs6APE6rjwWcj4CaOkGaIIZybPucz1FHvCuyeYVBmkBhAArIL6XcEiCvfCzkNMOpCeRPoPMXgFyACAPOcnAYFLK7fSrkDAR6rQmnAe/KBfmBNhQCDbkGtP0yyO8gsU + FHLYgL4EClGgvgDR9zudcCrT9PchVX4q49YmKc5AmkLNBsQDyOygsQK4iygCQoo8FHLGg0AcFIDQm3gPpvXg1zlu88j ++ 2ACFPB51CAmgbf9xYcIGEAAEDSAWM1ATAAC4CbdSzzGZLwAAAABJRU5ErkJggg ==

data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAABAAAAAQCAYAAAAf8/9hAAAA+klEQVR4AWMgBnwr4pRloAR8KuA89KmAK4V8A/LZ1YGGvPiQy65MtCaQjR8LuDxh/M8FXNlAQ078D2VgJs6APE6rjwWcj4CaOkGaIIZybPucz1FHvCuyeYVBmkBhAArIL6XcEiCvfCzkNMOpCeRPoPMXgFyACAPOcnAYFLK7fSrkDAR6rQmnAe/KBfmBNhQCDbkGtP0yyO8gsU+FHLYgL4EClGgvgDR9zudcCrT9PchVX4q49YmKc5AmkLNBsQDyOygsQK4iygCQoo8FHLGg0AcFIDQm3gPpvXg1zlu88j++2ACFPB51CAmgbf9xYcIGEAAEDSAWM1ATAAC4CbdSzzGZLwAAAABJRU5ErkJggg==

我从 GitHub 下载了一个网络浏览器开源.在这个项目中，程序员做到了这一点，这是可行的:

I download a web browser open source from GitHub. In this project, the Programmer does this and this is worked:

 public void onCreateContextMenu(ContextMenu menu, View v, ContextMenuInfo menuInfo) {
    Handler mHandler = new Handler() {
     @Override
        public void handleMessage(Message msg) {
            // Get link-URL.
            String url = (String) msg.getData().get("url");
            Log.i("get url" , url);
        }
    };

所以我在我的应用程序中编写了这段代码，但是 handleMessage 没有运行.使用 handleMessage 方法是否需要做其他事情?

So I write this code in my app, But handleMessage not be run. Do I need to do anything else to use handleMessage method?

您知道在谷歌搜索结果中获取网址的另一种方法吗?

Do you know another way to get a URL in google search results?

推荐答案

终于，几天后，我找到了解决方案.请尝试这种方式:

Finally, after days, I found a solution. Please try this way:

    @Override
    public void onCreateContextMenu(@NonNull ContextMenu menu, @NonNull View v, ContextMenu.ContextMenuInfo menuInfo) {
    super.onCreateContextMenu(menu, v, menuInfo);

    String url = null, imageUrl = null;
    WebView.HitTestResult result = ((WebView) v).getHitTestResult();
    switch (result.getType()) {
        case WebView.HitTestResult.SRC_ANCHOR_TYPE:
            url = result.getExtra();
            break;
        case WebView.HitTestResult.IMAGE_TYPE:
            imageUrl = result.getExtra();
            break;
        case WebView.HitTestResult.SRC_IMAGE_ANCHOR_TYPE:
        case WebView.HitTestResult.EMAIL_TYPE:
        case WebView.HitTestResult.UNKNOWN_TYPE:
            Handler handler = new Handler();
            Message message = handler.obtainMessage();
            ((WebView) v).requestFocusNodeHref(message);
            url = message.getData().getString("url");
            if ("".equals(url)) {
                url = null;
            }
            imageUrl = message.getData().getString("src");
            if ("".equals(imageUrl)) {
                imageUrl = null;
            }
            break;
    }
    showLongPressMenu(url, imageUrl);

}

这篇关于如何在长按中从网络视图中获取 URL?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！